Chapter 4, Problem 10CR

To determine

To find the factors of the polynomial $4t^2+4t+1$

Answer to Problem 10CR

Option(c)

Explanation of Solution

Given information: $4t^2+4t+1$

Formula used: ${(a+b)}^2=a^2+b^2+2ab$

Calculation :

Above expression can be written as:

  $\begin{array}{l}4t^2+4t+1\\ $ ={(2t)}^2+2.2t+1$$ ={(2t+1)}^2$\end{array}$

Hence, the factor of the polynomial is ${(2t+1)}^2$