Chapter 4, Problem 102IAE

Interpretation Introduction

Interpretation:

The volume of 0.0175M ${\text{CH}}_{\text{3}}\text{OH}$ that must be added to 50 mL of 0.0248M ${\text{CH}}_{\text{3}}\text{OH}$ to form a resulting solution with molarity of 0.0200M should be determined.

Concept introduction:

The molarity of a solute in a solution is determined by dividing the moles of solute by the volume of the solution in liter.

$M=\frac{n}{V\left(\text{L}\right)}$

Here, n is number of moles of solute and V is volume of solution in L.