(a)
Interpretation:
The water (
Concept introduction:
Boiling points: The every chemical compounds is the particular temperature at which its liquid from becomes a gas or (vaporizes). For a compound to vaporize, the forces that hold the individual molecules close to each other in the liquid must be overcome.
Than the boiling point of a each compound depends on the strength of the attractive forces between the individual molecules. If the molecules are held together by strong force then a great deal of energy will be need to pull the molecules away from each other and the compound will have a high boiling point.
On the other hand, if the molecules are held together by weak forces only a small of energy be need to pull the molecules away from each other and the compound will have a low boiling point.
Dipole interaction: The boiling points of all organic molecules like (ether,
(b)
Interpretation:
The water (H2O) molecule has higher boiling point when compare to other molecules of given in the statement why, this comparison must be explain in each statements.
Concept introduction:
Boiling points: The every chemical compounds is the particular temperature at which its liquid from becomes a gas or (vaporizes). For a compound to vaporize, the forces that hold the individual molecules close to each other in the liquid must be overcome.
Than the boiling point of a each compound depends on the strength of the attractive forces between the individual molecules. If the molecules are held together by strong force then a great deal of energy will be need to pull the molecules away from each other and the compound will have a high boiling point.
On the other hand, if the molecules are held together by weak forces only a small of energy be need to pull the molecules away from each other and the compound will have a low boiling point.
Dipole interaction: The boiling points of all organic molecules like (ether, alkyl halide, amines, alcohols) also increase molecular weight because in the London dispersion forces. The boling points of these compounds, however are also affected the polar (C-Z) bonds here (Z
(c)
Interpretation:
The water (H2O) molecule has higher boiling point when compare to other molecules of given in the statement why, this comparison must be explain in each statements.
Concept introduction:
Boiling points: The every chemical compounds is the particular temperature at which its liquid from becomes a gas or (vaporizes). For a compound to vaporize, the forces that hold the individual molecules close to each other in the liquid must be overcome.
Than the boiling point of a each compound depends on the strength of the attractive forces between the individual molecules. If the molecules are held together by strong force then a great deal of energy will be need to pull the molecules away from each other and the compound will have a high boiling point.
On the other hand, if the molecules are held together by weak forces only a small of energy be need to pull the molecules away from each other and the compound will have a low boiling point.
Dipole interaction: The boiling points of all organic molecules like (ether, alkyl halide, amines, alcohols) also increase molecular weight because in the London dispersion forces. The boling points of these compounds, however are also affected the polar (C-Z) bonds here (Z= N, O, F, Cl). Generally alcohols have higher boiling point when compare to other organic molecules, because addition of London dispersion forces and the dipole-dipole interaction of the polar C-O bond, alcohol can from hydrogen bonds.
d)
Interpretation:
The H-F molecule has higher boiling point when compare to other molecules of given in the statement why, this comparison must be explain in each statements.
Concept introduction:
Boiling points: The every chemical compounds is the particular temperature at which its liquid from becomes a gas or (vaporizes). For a compound to vaporize, the forces that hold the individual molecules close to each other in the liquid must be overcome.
Than the boiling point of a each compound depends on the strength of the attractive forces between the individual molecules. If the molecules are held together by strong force then a great deal of energy will be need to pull the molecules away from each other and the compound will have a high boiling point.
On the other hand, if the molecules are held together by weak forces only a small of energy be need to pull the molecules away from each other and the compound will have a low boiling point.
Dipole interaction: The boiling points of all organic molecules like (ether, alkyl halide, amines, alcohols) also increase molecular weight because in the London dispersion forces. The boling points of these compounds, however are also affected the polar (C-Z) bonds here (Z= N, O, F, Cl). Generally alcohols have higher boiling point when compare to other organic molecules, because addition of London dispersion forces and the dipole-dipole interaction of the polar C-O bond, alcohol can from hydrogen bonds.

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Chapter 3 Solutions
CHEM 262 ORG CHEM EBOOK DIGITAL DELIVERY
- When anisole is treated with excess bromine, the reaction gives a product which shows two singlets in 1H NMR. Draw the product.arrow_forward(ii) Draw a reasonable mechanism for the following reaction: CI NaOH heat OH (hint: SNAr Reaction) :arrow_forwardDraw the major product in each of the following reaction:arrow_forward
- Draw the mechanism for the following Friedel-Craft reaction. AlBr3 Brarrow_forward(a) Draw the structures of A and B in the following reaction. (i) NaNH2, NH3(1) A + B (ii) H3O+arrow_forwardFor the reaction 2 N2O5(g) → 4 NO2(g) + O2(g), the following mechanism has been proposed: N2O5 →> NO₂+ NO3_(K1) NO2 + NO3 → N2O5 (k-1) NO2 + NO3 → → NO2 + O2 + NO (K2) NO + N2O5- NO2 + NO2 + NO2 (K3) d[N₂O5] __2k‚k₂[N2O5] Indicate whether the following rate expression is acceptable: dt k₁₁+ k₂arrow_forward
- Consider the following decomposition reaction of N2O5(g): For the reaction 2 N2O5(g) → 4 NO2(g) + O2(g), the following mechanism has been proposed: N2O5 → NO2 + NO3 (K1) NO2 + NO3 → N2O5 (k-1) NO2 + NO3 → NO2 + O2 + NO (K2) NO + N2O5 → NO2 + NO2 + NO2 (K3) Indicate whether the following rate expression is acceptable: d[N2O5] = -k₁[N₂O₂] + K¸₁[NO₂][NO3] - K¸[NO₂]³ dtarrow_forwardIn a reaction of A + B to give C, another compound other than A, B or C may appear in the kinetic equation.arrow_forwardFor the reaction 2 N2O5(g) → 4 NO2(g) + O2(g), the following mechanism has been proposed: N2O5 →> NO₂+ NO3_(K1) NO2 + NO3 → N2O5 (k-1) NO2 + NO3 → → NO2 + O2 + NO (K2) NO + N2O5- NO2 + NO2 + NO2 (K3) d[N₂O5] __2k‚k₂[N2O5] Indicate whether the following rate expression is acceptable: dt k₁₁+ k₂arrow_forward
- Given the reaction R + Q → P, indicate the rate law with respect to R, with respect to P and with respect to P.arrow_forwardSteps and explanations. Also provide, if possible, ways to adress this kind of problems in general.arrow_forwardk₁ Given the reaction A B, indicate k-1 d[A] (A). the rate law with respect to A: (B). the rate law with respect to B: d[B] dt dtarrow_forward
- Chemistry by OpenStax (2015-05-04)ChemistryISBN:9781938168390Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark BlaserPublisher:OpenStaxChemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage Learning

