Bundle: Electricity For Refrigeration, Heating, And Air Conditioning, 10th + Refrigeration And Air Conditioning Technology, 8th + Mindtap Hvac, 4 ... Whitman/johnson's Refrigeration And Air Condi
8th Edition
ISBN: 9780357261385
Author: Russell E. Smith
Publisher: Cengage Learning
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Chapter 39, Problem 21RQ
What is the function of flame safeguard controls?
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Procedure:1- Cartesian system, 2D3D,type of support2- Free body diagram3 - Find the support reactions4- If you find a negativenumber then flip the force5- Find the internal force3D∑Fx=0∑Fy=0∑Fz=0∑Mx=0∑My=0\Sigma Mz=02D\Sigma Fx=0\Sigma Fy=0\Sigma Mz=05- Use method of sectionand cut the elementwhere you want to find
Procedure:1- Cartesian system, 2D3D,type of support2- Free body diagram3 - Find the support reactions4- If you find a negativenumber then flip the force5- Find the internal force3D∑Fx=0∑Fy=0∑Fz=0∑Mx=0∑My=0\Sigma Mz=02D\Sigma Fx=0\Sigma Fy=0\Sigma Mz=05- Use method of sectionand cut the elementwhere you want to findthe internal force andkeep either side of the
Procedure:
1- Cartesian system, 2D3D,
type of support
2- Free body diagram
3 - Find the support reactions
4- If you find a negative
number then flip the force
5- Find the internal force
3D
∑Fx=0
∑Fy=0
∑Fz=0
∑Mx=0
∑My=0
ΣMz=0
2D
ΣFx=0
ΣFy=0
ΣMz=0
5- Use method of section
and cut the element
where you want to find
the internal force and
keep either side of the
Chapter 39 Solutions
Bundle: Electricity For Refrigeration, Heating, And Air Conditioning, 10th + Refrigeration And Air Conditioning Technology, 8th + Mindtap Hvac, 4 ... Whitman/johnson's Refrigeration And Air Condi
Ch. 39 - Define a residential energy audit.Ch. 39 - Name and briefly explain the three broad...Ch. 39 - Name four nationally recognized energy...Ch. 39 - Performing a home energy audit starts with a...Ch. 39 - Name seven base loads, or LAMEL loads, as they...Ch. 39 - Name and briefly explain the five most common...Ch. 39 - One Pascal (Pa) is equal to how many inches of...Ch. 39 - One inch of water column (in. WC) is equal to how...Ch. 39 - Briefly describe a blower door test.Ch. 39 - What can an infrared scanning camera do for an...
Ch. 39 - Briefly describe what a duct blower's function is...Ch. 39 - Briefly describe how to check for duct leakage to...Ch. 39 - Briefly describe and write the equation for...Ch. 39 - Briefly describe and write the equation for...Ch. 39 - When performing a combustion efficiency test,...Ch. 39 - Briefly define draft as it applies to a combustion...Ch. 39 - Briefly define backdrafting as it applies to a...Ch. 39 - Briefly define spillage as it applies to a...Ch. 39 - Name four causes for backdrafting....Ch. 39 - What will a cracked heat exchanger cause in a...Ch. 39 - What is the function of flame safeguard controls?Ch. 39 - Name three common flame safeguard controls. _____,...Ch. 39 - Define primary air as it applies to a combustion...Ch. 39 - Define secondary air as it applies to a combustion...Ch. 39 - Define dilution air as it applies to a combustion...Ch. 39 - Define excess air as it applies to a combustion...Ch. 39 - What is the difference between an induced-draft...Ch. 39 - What is the difference between over-the-fire draft...Ch. 39 - What is meant by a direct-vented,...Ch. 39 - What is meant by an energy conservation measure...Ch. 39 - What is the difference between a base load and...Ch. 39 - Define a home energy index.
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- Procedure:1- Cartesian system, 2D3D,type of support2- Free body diagram3 - Find the support reactions4- If you find a negativenumber then flip the force5- Find the internal force3D∑Fx=0∑Fy=0∑Fz=0∑Mx=0∑My=0\Sigma Mz=02D\Sigma Fx=0\Sigma Fy=0\Sigma Mz=05- Use method of sectionand cut the elementwhere you want to findthe internal force andkeep either side of thearrow_forwardProcedure: 1- Cartesian system, 2(D)/(3)D, type of support 2- Free body diagram 3 - Find the support reactions 4- If you find a negative number then flip the force 5- Find the internal force 3D \sum Fx=0 \sum Fy=0 \sum Fz=0 \sum Mx=0 \sum My=0 \Sigma Mz=0 2D \Sigma Fx=0 \Sigma Fy=0 \Sigma Mz=0 5- Use method of section and cut the element where you want to find the internal force and keep either side of the sectionarrow_forwardProcedure: 1- Cartesian system, 2(D)/(3)D, type of support 2- Free body diagram 3 - Find the support reactions 4- If you find a negative number then flip the force 5- Find the internal force 3D \sum Fx=0 \sum Fy=0 \sum Fz=0 \sum Mx=0 \sum My=0 \Sigma Mz=0 2D \Sigma Fx=0 \Sigma Fy=0 \Sigma Mz=0 5- Use method of section and cut the element where you want to find the internal force and keep either side of the sectionarrow_forward
- For each system below with transfer function G(s), plot the pole(s) on the s-plane. and indicate whether the system is: (a) "stable" (i.e., a bounded input will always result in a bounded output), (b) "marginally stable," or (c) "unstable" Sketch a rough graph of the time response to a step input. 8 a) G(s) = 5-5 8 b) G(s) = c) G(s) = = s+5 3s + 8 s² - 2s +2 3s +8 d) G(s): = s²+2s+2 3s+8 e) G(s): = s² +9 f) G(s): 8 00 == Sarrow_forwardPlease answer the following question. Include all work and plase explain. Graphs are provided below. "Consider the Mg (Magnesium) - Ni (Nickel) phase diagram shown below. This phase diagram contains two eutectic reactions and two intermediate phases (Mg2Ni and MgNi2). At a temperature of 505oC, determine what the composition of an alloy would need to be to contain a mass fraction of 0.20 Mg and 0.80 Mg2Ni."arrow_forwardThe triangular plate, having a 90∘∘ angle at AA, supports the load PP = 370 lblb as shown in (Figure 1).arrow_forward
- Design a 4-bar linkage to carry the body in Figure 1 through the two positions P1 and P2 at the angles shown in the figure. Use analytical synthesis with the free choice values z = 1.075, q= 210°, ß2 = −27° for left side and s = 1.24, y= 74°, ½ = − 40° for right side. φ 1.236 P2 147.5° 210° 2.138 P1 Figure 1 Xarrow_forwardDesign a 4-bar linkage to carry the body in Figure 1 through the two positions P1 and P2 at the angles shown in the figure. Use analytical synthesis with the free choice values z = 1.075, q= 210°, B₂ = −27° for left side and s = 1.24, y= 74°, ½ = − 40° for right side. 1.236 P2 147.5° 210° P1 Figure 1 2.138 Xarrow_forwardcan you explain how in a coordinate frame transformation: v = {v_n}^T {n-hat} and then it was found that {n-hat} = [C]^T {b-hat} so v_n = {v_n}^T [C]^T {b-hat}, how does that equation go from that to this --> v_n = [C]^T v_barrow_forward
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