Chapter 39, Problem 1PLA

50639-39-1PLA                  AID: 1825 | 11/04/2020

To determine

The equation for the power dissipated by a resistor of resistance $R$, current $I$ and voltage $V$.

Answer to Problem 1PLA

The equation for the power dissipated by a resistor of resistance $R$, current $I$ and voltage $V$ is $P=\frac{V^2}{R}=I^{2}R=VI$.

Explanation of Solution

Write the equation for the power dissipated by a resistor of resistance $R$, current $I$ and voltage $V$

    $P=\frac{V^2}{R}=I^{2}R=VI$

Here, $P$ is the power, $V$ is the voltage across the resistor, $R$ is the resistance of the resistor and $I$ is the current across the resistor.

Conclusion:

Thus, the equation for the power dissipated by a resistor of resistance $R$, current $I$ and voltage $V$ is $P=\frac{V^2}{R}=I^{2}R=VI$.