PRESCOTT'S MICROBIOLOGY
11th Edition
ISBN: 2818440045677
Author: WILLEY
Publisher: MCG
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Chapter 38.3, Problem 2MI
Summary Introduction
To determine: The location of residency of HSV-2 during latent infection.
Introduction: Viruses always come from a living source as they cannot multiply in air. Herpes simplex virus is responsible for causing genital herpes mainly HSV-2. This virus is transferred from one to another through sexual contact.
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Design a grafting experiment to determine if limb mesoderm determines forelimb / hindlimb identity. Include the experiment, a control, and an interpretation in your answer.
The Snapdragon is a popular garden flower that comes in a variety of colours, including red, yellow, and orange. The genotypes and associated phenotypes for some of these flowers are as follows:
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orange because A is epistatic to B
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A sample of blood was taken from the above individual and prepared for haemoglobin analysis. However, when water was added the cells did not lyse and looked normal in size and shape. The technician suspected that they had may have made an error in the protocol – what is the most likely explanation?
The cell membranes are more resistant than normal.
An isotonic solution had been added instead of water.
A solution of 0.1 M NaCl had been added instead of water.
Not enough water had been added to the red blood cell pellet.
The man had sickle-cell anaemia.
Chapter 38 Solutions
PRESCOTT'S MICROBIOLOGY
Ch. 38.1 - Prob. 1MICh. 38.1 - Why is it thought that the characteristic rash is...Ch. 38.1 - Prob. 3MICh. 38.1 - Prob. 1CCCh. 38.1 - Prob. 2CCCh. 38.1 - Prob. 3CCCh. 38.1 - Prob. 4CCCh. 38.1 - Prob. 5CCCh. 38.1 - Prob. 6CCCh. 38.1 - Prob. 7CC
Ch. 38.3 - Prob. 1MICh. 38.3 - Prob. 2MICh. 38.3 - Prob. 1CCCh. 38.3 - Prob. 2CCCh. 38.3 - Prob. 3CCCh. 38.3 - Prob. 4CCCh. 38.3 - Prob. 5CCCh. 38.3 - Prob. 6CCCh. 38.4 - Prob. 1CCCh. 38.4 - Prob. 2CCCh. 38.4 - Prob. 3CCCh. 38.4 - Prob. 4CCCh. 38.5 - Prob. 1MICh. 38.5 - Prob. 1CCCh. 38.5 - Prob. 2CCCh. 38.5 - Prob. 3CCCh. 38.6 - How are prions different from viruses? How are...Ch. 38.6 - In what way are spongiform encephalopathies...Ch. 38 - Prob. 1RCCh. 38 - Prob. 2RCCh. 38 - Prob. 3RCCh. 38 - Prob. 1ALCh. 38 - Prob. 2ALCh. 38 - Prob. 3ALCh. 38 - Prob. 4ALCh. 38 - Prob. 5ALCh. 38 - Prob. 6AL
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- A sample of blood was taken from the above individual and prepared for haemoglobin analysis. However, when water was added the cells did not lyse and looked normal in size and shape. The technician suspected that they had may have made an error in the protocol – what is the most likely explanation? The cell membranes are more resistant than normal. An isotonic solution had been added instead of water. A solution of 0.1 M NaCl had been added instead of water. Not enough water had been added to the red blood cell pellet. The man had sickle-cell anaemia.arrow_forwardWith reference to their absorption spectra of the oxy haemoglobin intact line) and deoxyhemoglobin (broken line) shown in Figure 2 below, how would you best explain the reason why there are differences in the major peaks of the spectra? Figure 2. SPECTRA OF OXYGENATED AND DEOXYGENATED HAEMOGLOBIN OBTAINED WITH THE RECORDING SPECTROPHOTOMETER 1.4 Abs < 0.8 06 0.4 400 420 440 460 480 500 520 540 560 580 600 nm 1. The difference in the spectra is due to a pH change in the deoxy-haemoglobin due to uptake of CO2- 2. There is more oxygen-carrying plasma in the oxy-haemoglobin sample. 3. The change in Mr due to oxygen binding causes the oxy haemoglobin to have a higher absorbance peak. 4. Oxy-haemoglobin is contaminated by carbaminohemoglobin, and therefore has a higher absorbance peak 5. Oxy-haemoglobin absorbs more light of blue wavelengths and less of red wavelengths than deoxy-haemoglobinarrow_forwardWith reference to their absorption spectra of the oxy haemoglobin intact line) and deoxyhemoglobin (broken line) shown in Figure 2 below, how would you best explain the reason why there are differences in the major peaks of the spectra? Figure 2. SPECTRA OF OXYGENATED AND DEOXYGENATED HAEMOGLOBIN OBTAINED WITH THE RECORDING SPECTROPHOTOMETER 1.4 Abs < 0.8 06 0.4 400 420 440 460 480 500 520 540 560 580 600 nm 1. The difference in the spectra is due to a pH change in the deoxy-haemoglobin due to uptake of CO2- 2. There is more oxygen-carrying plasma in the oxy-haemoglobin sample. 3. The change in Mr due to oxygen binding causes the oxy haemoglobin to have a higher absorbance peak. 4. Oxy-haemoglobin is contaminated by carbaminohemoglobin, and therefore has a higher absorbance peak 5. Oxy-haemoglobin absorbs more light of blue wavelengths and less of red wavelengths than deoxy-haemoglobinarrow_forward
- Which ONE of the following is FALSE regarding haemoglobin? It has two alpha subunits and two beta subunits. The subunits are joined by disulphide bonds. Each subunit covalently binds a haem group. Conformational change in one subunit can be transmitted to another. There are many variant ("mutant") forms of haemoglobin that are not harmful.arrow_forwardWhich ONE of the following is FALSE regarding haemoglobin? It has two alpha subunits and two beta subunits. The subunits are joined by disulphide bonds. Each subunit covalently binds a haem group. Conformational change in one subunit can be transmitted to another. There are many variant ("mutant") forms of haemoglobin that are not harmful.arrow_forwardDuring a routine medical check up of a healthy man it was found that his haematocrit value was highly unusual – value of 60%. What one of the options below is the most likely reason? He will have a diet high in iron. He is likely to be suffering from anaemia. He lives at high altitude. He has recently recovered from an accident where he lost a lot of blood. He has a very large body size.arrow_forward
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