Physics for Science and Engineering With Modern Physics, VI - Student Study Guide
4th Edition
ISBN: 9780132273244
Author: Doug Giancoli
Publisher: PEARSON
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Question
Chapter 38, Problem 51GP
To determine
The position uncertainty for the electron in the ground state of the hydrogen atom and to compare it with the Bohr’s radius.
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Check out a sample textbook solutionStudents have asked these similar questions
1. (a) Which "bold and daring" proposal did Bohr make to overcome the predictions of
classical mechanics of an electron spiralling into the nucleus?
(b) Explaining all the assumptions made and the terms used, show that the radius for the nth
orbit of Bohr's model of the hydrogen atom is given by:
h?
r. =
47 kme?
Show also, that the energy of the electron in the nth orbit is given by:
me
E,
%3D
2. (i)What do you understand by Pauli's exclusion principle?
(ii) Write down all possible combinations of the quantum numbers for electrons filling
completely the p shell for n=2
3:09 O O O 63° A X •
N N O 5G „ll
Quizzes
a
(absorption)
Brackett
series
Paschen
series
Lyman
series
(emission)
Balmer series
Paschen
series
(emission)
n= 2
n=3
n=4
....
Lyman series
n-5
(a)
(b)
e These pictures refer to the energy levels
of a hydrogen atom.
You can find the error in both parts, (a) and
(b). The arrows labeled "emission" in (a), and
all the arrows in (b), indicate a transition in
which an electron jumps from a higher-
energy state to a lower-energy state. The
different "series" of emission lines are
characterized by the index n of the low-
energy state in which the electron ends up.
In particular, the Lyman series consists of all
transitions that end up in the n=1 energy
level, with an initial energy level that
corresponds to the label n = 2, 3, 4, 5, etc.
One of these values of n is not shown as an
arrow in the Lyman emission series in figures
(a) or (b). This is a significant error because
that particular spectral line is very important
in astronomy.
Pick the value…
Based on the Bohr model, derive the expression for the Bohr radius for hydrogen atom from scratch. Express you answer in unit of Angstrom.
Chapter 38 Solutions
Physics for Science and Engineering With Modern Physics, VI - Student Study Guide
Ch. 38.3 - Prob. 1AECh. 38.8 - Prob. 1BECh. 38.8 - Prob. 1CECh. 38.9 - Prob. 1DECh. 38 - Prob. 1QCh. 38 - Prob. 2QCh. 38 - Prob. 3QCh. 38 - Prob. 4QCh. 38 - Would it ever be possible to balance a very sharp...Ch. 38 - Prob. 6Q
Ch. 38 - Prob. 7QCh. 38 - Prob. 8QCh. 38 - Prob. 9QCh. 38 - Prob. 10QCh. 38 - Prob. 11QCh. 38 - Prob. 12QCh. 38 - Prob. 13QCh. 38 - Prob. 14QCh. 38 - Prob. 15QCh. 38 - Prob. 16QCh. 38 - Prob. 17QCh. 38 - Prob. 18QCh. 38 - Prob. 1PCh. 38 - Prob. 2PCh. 38 - Prob. 3PCh. 38 - Prob. 4PCh. 38 - Prob. 5PCh. 38 - Prob. 6PCh. 38 - Prob. 7PCh. 38 - Prob. 8PCh. 38 - Prob. 9PCh. 38 - Prob. 10PCh. 38 - Prob. 11PCh. 38 - Prob. 12PCh. 38 - Prob. 13PCh. 38 - Prob. 14PCh. 38 - Prob. 15PCh. 38 - Prob. 16PCh. 38 - Prob. 17PCh. 38 - Prob. 18PCh. 38 - Prob. 19PCh. 38 - Prob. 20PCh. 38 - Prob. 21PCh. 38 - Prob. 22PCh. 38 - Prob. 23PCh. 38 - Prob. 24PCh. 38 - Prob. 25PCh. 38 - Prob. 26PCh. 38 - Prob. 27PCh. 38 - Prob. 28PCh. 38 - Prob. 29PCh. 38 - Prob. 30PCh. 38 - Prob. 31PCh. 38 - Prob. 32PCh. 38 - Prob. 33PCh. 38 - Prob. 34PCh. 38 - Prob. 35PCh. 38 - Prob. 36PCh. 38 - Prob. 37PCh. 38 - Prob. 38PCh. 38 - Prob. 39PCh. 38 - Prob. 40PCh. 38 - Prob. 41PCh. 38 - Prob. 42PCh. 38 - Prob. 43PCh. 38 - Prob. 44PCh. 38 - Prob. 45PCh. 38 - Prob. 46GPCh. 38 - Prob. 47GPCh. 38 - Prob. 48GPCh. 38 - Prob. 49GPCh. 38 - Prob. 50GPCh. 38 - Prob. 51GPCh. 38 - Prob. 52GPCh. 38 - Prob. 53GPCh. 38 - Prob. 54GPCh. 38 - Prob. 55GPCh. 38 - Prob. 56GPCh. 38 - Prob. 57GPCh. 38 - Prob. 58GPCh. 38 - Prob. 59GP
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- Do the Balmer series and the Lyman series overlap? Why? Why not? (Hint: calculate the shortest Balmer line and the longest Lyman line.)arrow_forwardCheck Your Understanding When an election in a hydrogen atom is in the first excited state, what prediction does the Bohr model give about its orbital speed and kinetic energy? What is the magnitude of its orbital angular momentum?arrow_forward(a) If one subshell of an atom has nine electrons in it, what is the minimum value of (b) What is the spectroscopic notation for this atom, if this subshell is part of the n = 3 shell?arrow_forward
- A triply ionized atom of betyllium Be3+ is a hydrogen-like ion. When Be3+ is in one of its excited states, its radius in this nth state is exactly the same as the radius of the first Bohr orbit of hydrogen. Find n and compute the ionization energy for this state of Be3+ .arrow_forwardWhat, if any, constraints does a value of m = 1 place on the other quantum numbers for an electron in an atom?arrow_forwardThe Balmer series for hydrogen was discovered before either the Lyman or the Paschen series. Why?arrow_forward
- If an atom has an election in the n = 5 state with m = 3, what are the possible values of l?arrow_forwardWhat is the radius of a hydrogen atom when the electron is in the first excited state?arrow_forwardAn atom has an electron with m1=2. What is the smallest value of n for this electron?arrow_forward
- Find the shortest wavelength in the Balmer series. In what part of the spectrum does this line lie?arrow_forwardAccording to the Schrodinger equation, what is the position of an electron in a hydrogen atom? Group of answer choices In a curricular orbit at the Bohr radius. In an elliptical orbit with a semimajor axis given by the Bohr radius. In a spherical orbit with a Bohr radius. In a distribution cloud with the most probably electron position being at the Bohr radius.arrow_forwardThe gravitational attraction between electron and proton in a hydrogen atom is weaker than the coulomb attraction by a factor of about 10-40. An alternative way of looking at this fact is to estimate the radius of the first Bohr orbit of a hydrogen atom if the electron and proton were bound by gravitational attraction. You will find the answer interesting.arrow_forward
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