Explanation 1) Concept: We know the formula for the energy of the photon. Form this, we can find the λ . We are given the relation between energy of photon and energy of scattered photons. From this, we can find the energy of the scattered photons. From this, we can find the wavelength of the scattered photons. Now using the formula for Compton shift. we can find the angle. 2) Formula: i) E = h c λ ii) ∆ λ = h m c 1 - cos ⁡ ϕ 3) Given: i) E = 200 k e V = 200 × 10 3 × 1.6 × 10 - 19 J = 320 × 10 - 16 J ii) E ' = 0.9 E 4) Calculation: We have E = h c λ We rearrange the equation to calculate value for λ : λ = h c E Substituting the values, we get λ = 6.63 × 10 - 34 × 3 × 10 8 320 × 10 - 16 λ = 6.22 × 10 - 12 m We have E ' = 0.9 E h c λ ' = 0.9 h c λ 1 λ ' = 0.9 λ λ ' = λ 0.9 λ ' = 6

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ISBN: 9781118230725

Author: David Halliday, Robert Resnick, Jearl Walker

Publisher: Wiley, John & Sons, Incorporated

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Chapter 38, Problem 39P

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The angle through which the proton should be scattered

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Chapter 38, Problem 38P

Chapter 38, Problem 40P

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T1. Calculate what is the received frequency when the car drives away from the radar antenna at a speed v of a) 1 m/s ( = 3.6 km/h), b) 10 m/s ( = 36 km/h), c) 30 m /s ( = 108 km/h) . The radar transmission frequency f is 24.125 GHz = 24.125*10^9 Hz, about 24 GHz. Speed of light 2.998 *10^8 m/s.

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Chapter 38 Solutions

Fundamentals of Physics Extended

Ch. 38 - Prob. 1Q Ch. 38 - Prob. 2Q Ch. 38 - Prob. 3Q Ch. 38 - Prob. 4Q Ch. 38 - Prob. 5Q Ch. 38 - Prob. 6Q Ch. 38 - Prob. 7Q Ch. 38 - Prob. 8Q Ch. 38 - Prob. 9Q Ch. 38 - Prob. 10Q

Ch. 38 - Prob. 11Q Ch. 38 - Prob. 12Q Ch. 38 - Prob. 13Q Ch. 38 - Prob. 14Q Ch. 38 - Prob. 15Q Ch. 38 - Prob. 16Q Ch. 38 - Prob. 1P Ch. 38 - Prob. 2P Ch. 38 - Prob. 3P Ch. 38 - Prob. 4P Ch. 38 - Prob. 5P Ch. 38 - Prob. 6P Ch. 38 - Prob. 7P Ch. 38 - Prob. 8P Ch. 38 - Prob. 9P Ch. 38 - Prob. 10P Ch. 38 - Prob. 11P Ch. 38 - Prob. 12P Ch. 38 - Prob. 13P Ch. 38 - Prob. 14P Ch. 38 - Prob. 15P Ch. 38 - Prob. 16P Ch. 38 - Prob. 17P Ch. 38 - Prob. 18P Ch. 38 - Prob. 19P Ch. 38 - Prob. 20P Ch. 38 - Prob. 21P Ch. 38 - Prob. 22P Ch. 38 - Prob. 23P Ch. 38 - Prob. 24P Ch. 38 - Prob. 25P Ch. 38 - Prob. 26P Ch. 38 - Prob. 27P Ch. 38 - Prob. 28P Ch. 38 - Prob. 29P Ch. 38 - Prob. 30P Ch. 38 - Prob. 31P Ch. 38 - Prob. 32P Ch. 38 - Prob. 33P Ch. 38 - Prob. 34P Ch. 38 - Prob. 35P Ch. 38 - Prob. 36P Ch. 38 - Prob. 37P Ch. 38 - Prob. 38P Ch. 38 - Prob. 39P Ch. 38 - Prob. 40P Ch. 38 - Prob. 41P Ch. 38 - Prob. 42P Ch. 38 - Prob. 43P Ch. 38 - Prob. 44P Ch. 38 - Prob. 45P Ch. 38 - Prob. 46P Ch. 38 - Prob. 47P Ch. 38 - Prob. 48P Ch. 38 - Prob. 49P Ch. 38 - Prob. 50P Ch. 38 - Prob. 51P Ch. 38 - Prob. 52P Ch. 38 - Prob. 53P Ch. 38 - Prob. 54P Ch. 38 - Prob. 55P Ch. 38 - Prob. 56P Ch. 38 - Prob. 57P Ch. 38 - Prob. 58P Ch. 38 - Prob. 59P Ch. 38 - Prob. 60P Ch. 38 - Prob. 61P Ch. 38 - Prob. 62P Ch. 38 - Prob. 63P Ch. 38 - Prob. 64P Ch. 38 - Prob. 65P Ch. 38 - Prob. 66P Ch. 38 - Prob. 67P Ch. 38 - Prob. 68P Ch. 38 - Prob. 69P Ch. 38 - Prob. 70P Ch. 38 - Prob. 71P Ch. 38 - Prob. 72P Ch. 38 - Prob. 73P Ch. 38 - Prob. 74P Ch. 38 - Prob. 75P Ch. 38 - Prob. 76P Ch. 38 - Prob. 77P Ch. 38 - Prob. 78P Ch. 38 - Prob. 79P Ch. 38 - Prob. 80P Ch. 38 - Prob. 81P Ch. 38 - Prob. 82P Ch. 38 - Prob. 83P Ch. 38 - Prob. 84P Ch. 38 - Prob. 85P Ch. 38 - Prob. 86P Ch. 38 - Prob. 87P Ch. 38 - Prob. 88P Ch. 38 - Prob. 89P Ch. 38 - Prob. 90P

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The angle through which the proton should be scattered

Solution Summary: The author explains that the angle through which the proton should be scattered is 44°.

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To find: The angle through which the proton should be scattered

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Chapter 38 Solutions

To find:

The angle through which the proton should be scattered