Explanation 1) Concept: The element will be suitable for making photocell if kinetic energy of photoelectron is positive. Therefore, it gives out electrons. K m a x > 0.0 And if K m a x < 0.0 , it will not eject electrons and is therefore not suitable for making photocell. 2) Formula: i) Photon energy ϵ = h c λ ii) K m a x = h c λ - ϕ 3) Given: Work function for elements i) Tantalum ϕ = 4.2 e V ii) Tungsten ϕ = 4.5 e V iii) Aluminum ϕ = 4.2 e V iv) Barium ϕ = 2.5 e V v) Lithium ϕ = 2.3 e V 4) Calculations: We know that visible light spectrum falls in the wavelength range ≈ 400 n m t o 700 n m . And the photon with wavelength λ = 400 n m will have most energy, and therefore ϵ = h c λ = 1240 e V

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Question

Chapter 38, Problem 18P

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Suitable elements for photocell from the given list

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Chapter 38, Problem 17P

Chapter 38, Problem 19P

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Chapter 38 Solutions

Fundamentals of Physics Extended

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