Manufacturing Engineering & Technology
7th Edition
ISBN: 9780133128741
Author: Serope Kalpakjian, Steven Schmid
Publisher: Prentice Hall
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Chapter 38, Problem 23QLP
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Explain the advantages of hierarchical coding.
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Chapter 38 Solutions
Manufacturing Engineering & Technology
Ch. 38 - In what ways have computers had an impact on...Ch. 38 - Describe the benefits of computer-integrated...Ch. 38 - What is a database? Why is it necessary?Ch. 38 - What is an STL file? What is it popularly used...Ch. 38 - What are the differences between the terms...Ch. 38 - Prob. 6RQCh. 38 - What do the following abbreviations mean:...Ch. 38 - Prob. 8RQCh. 38 - Describe the purposes of process planning. How...Ch. 38 - Describe the features of a routing sheet. Why is...
Ch. 38 - What are the advantages of simulation of...Ch. 38 - What is group technology? Why was it...Ch. 38 - Explain the three types of GT coding:...Ch. 38 - Describe what is meant by the term...Ch. 38 - What does classification and coding mean in...Ch. 38 - Prob. 16RQCh. 38 - Describe your observations regarding Figs. 38.1...Ch. 38 - Prob. 19QLPCh. 38 - Give examples of primitives of solids other than...Ch. 38 - Describe your understanding of the octree...Ch. 38 - Explain the logic behind the arrangements shown...Ch. 38 - Prob. 23QLPCh. 38 - What is the difference between a variant system...Ch. 38 - Referring to Fig. 38.3, explain the advantages ofa...Ch. 38 - Prob. 26QLPCh. 38 - Describe situations that would require a design...Ch. 38 - Prob. 28QLPCh. 38 - How would you describe the principle of...Ch. 38 - Review various manufactured parts illustrated in...Ch. 38 - Think of a simple part and make a decision-tree...Ch. 38 - Review the machine arrangements in Fig. 38.12...Ch. 38 - Think of a simple product and make a routing...Ch. 38 - Review Fig. 38.9, and prepare a routing sheet for...
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- Q1] B/ (16 Marks) To produce a lightweight epoxy part to provide thermal insulation. The available material are hollow glass beads for which the outside diameter is 1.6 mm and the wall thickness is 0.04 mm. Determine the weight and number of beads that must be added to the epoxy to produce a 0.5 kg of composite with a density of 0.65 g/cm³. The density of the glass is 2.5 g/cm³ and that of the epoxy is 1.25 g/cm³.arrow_forwardBelow is a projection of the inertia ellipsoid in the b1-b2 plane (b1 and b2 are unit vectors). All points on the ellipsoid surface represent moments of inertia in various directions. The distance R is related to the distance D such that R = md. Determine m.arrow_forwardBelow is a projection of the inertia ellipsoid in the b1-b2 plane (b1 and b2 are unit vectors). All points on the ellipsoid surface represent moments of inertia in various directions. Determine I_aa ( moment of inertia) for direction n_a (this is a unit vector).arrow_forward
- The problems are generally based on the following model: A particular spacecraft can be represented as a single axisymmetric rigid body B. Let n₂ be inertially fixed unit vectors; then, 6, are parallel to central, principal axes. To make the mathematics simpler, introduce a frame C where n₂ = ĉ₁ = b; initially. 6₁ Assume a mass distribution such that J =₁₁• B* •b₁ = 450 kg - m² I = b² •Ï¾˜ • b₂ = b¸ •Ï¾* •b¸ = 200 kg - m² K J-I C³ =r₁₁ = r₁₁arrow_forwardThe problems are generally based on the following model: A particular spacecraft can be represented as a single axisymmetric rigid body B. Let n₂ be inertially fixed unit vectors; then, 6, are parallel to central, principal axes. To make the mathematics simpler, introduce a frame C where n₂ = ĉ₁ = b; initially. 6₁ Assume a mass distribution such that J =₁₁• B* •b₁ = 450 kg - m² I = b² •Ï¾˜ • b₂ = b¸ •Ï¾* •b¸ = 200 kg - m² K J-I C³ =r₁₁ = r₁₁arrow_forwardThe problems are generally based on the following model: A particular spacecraft can be represented as a single axisymmetric rigid body B. Let n₂ be inertially fixed unit vectors; then, 6, are parallel to central, principal axes. To make the mathematics simpler, introduce a frame C where n₂ = ĉ₁ = b; initially. 6₁ Assume a mass distribution such that J =₁₁• B* •b₁ = 450 kg - m² I = b² •Ï¾˜ • b₂ = b¸ •Ï¾* •b¸ = 200 kg - m² K J-I C³ =r₁₁ = r₁₁arrow_forward
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