Degarmo's Materials And Processes In Manufacturing
13th Edition
ISBN: 9781119492825
Author: Black, J. Temple, Kohser, Ronald A., Author.
Publisher: Wiley,
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Textbook Question
Chapter 38, Problem 1RQ
What are some joining conditions where welding might not be the best choice?
Expert Solution & Answer
To determine
The joining conditions where welding might not be best choice.
Explanation of Solution
Welding is the process of joining two metals by melting the materials. The metals may join with the help of filler material or non-filler material. The filler material is consumable material by which the welding cost increases. Most of the manufacturing industries use this technique for joining metals. The welding process is used to create permanent joints, which are not easy to dislocate without deforming the shape of the material.
The conditions where this technique is not used are as follows,
- It is not used where temporary joints are needed.
- It is not used where the welding cost is high.
- It is not used in materials that possess poor weldability.
- It is not used in the materials which have a shallow melting temperature. For this type of material, low temperature joining methods are preferred.
- It is not used where joints involve thin material.
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Students have asked these similar questions
13.1
Determine F2 and F2 for the following configura-
tions using the reciprocity theorem and other basic
shape factor relations. Do not use tables or charts.
(a) Small sphere of area A, under a concentric hemi-
sphere of area A₂ = 3A₁
A₂
A1
(a)
(b) Long duct. Also, what is F₁₂?
A₂
Αν
(b)
(c) Long inclined plates (point B is directly above the
center of A₁)
B
100 mm
A₂
- 220 mm
(c)
(d) Long cylinder lying on infinite plane
+
A₁
Az
(d)
(e) Hemisphere-disk arrangement
-A₂, hemisphere,
diameter D
A₂
A₁, disk,
diameter D/2
(e)
(f) Long, open channel
1 m
AA₂
2 m
(f)
(g) Long cylinders with A₁ = 4A₁. Also, what is F₁₂?
-D₁
A1
-A₂
-D2
(e)
(h) Long, square rod in a long cylinder. Also, what
is F22?
w=D/5
18
A₁
-A2
(h)
-D
13.9 Determine the shape factor, F12, for the rectangles
shown.
6 m
1
3 m
6 m
1 m
2
6 m
1
0.5 m
2
1 m
(a) Perpendicular rectangles
without a common edge.
-1 m.
(b) Parallel rectangles of
unequal areas.
I keep getting the wrong answer i have gotten 6519.87 and 319.71
Chapter 38 Solutions
Degarmo's Materials And Processes In Manufacturing
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