Explanation Given information: The given function is f ( x ) = 2.1 x 2 + 3 x + 5 . Formula used: The approximate change in function f ( x ) is, Δ [ f ( x ) ] = f ′ ( x ) Δ x (1) Calculation: The value of Δ x in function f ( x ) changes from a = 3 to b = 2.95 . Δ x = b − a = 2.95 − 3 = − 0.05 The function is f ( x ) = 2.1 x 2 + 3 x + 5 . Differentiate above function with respect to x and get the value of f ′ ( x ) . d d x [ f ( x ) ] = d d x ( 2.1 x 2 + 3 x + 5 ) = 2.1 × 2 x + 3 ( − 1 2 x − 3 2 ) + 0 = ( 4.2 x + ( − 3 2 x − 3 2 ) ) Substitute ( 4.2 x + ( − 3 2 x − 3 2 ) ) for f ′ ( x ) in equation (1). Δ f ( x ) = ( 4

Applied Calculus for the Managerial, Life, and Social Sciences (MindTap Course List)

10th Edition

ISBN: 9781305657861

Author: Soo T. Tan

Publisher: Cengage Learning

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When a large number of trials are performed for any random variable ‘X’, the predicted result is most likely the mean of all the outcomes for the random variable and it is known as expected value also known as expectation. The expected value, also known …

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Chapter 3.7, Problem 6TE

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To find: The approximate value of the given function.

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Chapter 3.7, Problem 5TE

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Chapter 3 Solutions

Applied Calculus for the Managerial, Life, and Social Sciences (MindTap Course List)

Ch. 3.1 - State the following rules of differentiation in...Ch. 3.1 - Prob. 2CQ Ch. 3.1 - Prob. 3CQ Ch. 3.1 - Prob. 4CQ Ch. 3.1 - Prob. 1E Ch. 3.1 - Prob. 2E Ch. 3.1 - Prob. 3E Ch. 3.1 - Prob. 4E Ch. 3.1 - Prob. 5E Ch. 3.1 - Prob. 6E

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The approximate value of the given function.

Solution Summary: The author calculates the approximate value of the function f(x), based on a formula.

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Chapter 3 Solutions