(a) Explanation Given: The distance between object location and retina is 50 cm and the distance between retina and cornea is 2.5 cm. Formula used: The formula to calculate the focal length is 1 f = 1 p + 1 q (1) Where f is focal length of thin lens, p is distance of the object from the lens and q is distance of object’s image from the lens. Calculation: The distance between object location and retina is 50 cm that mean the value of p is 50cm. The distance between cornea and retina is 2.5 that mean the distance of object’s image from the lens q is 2.5 cm since, an object image is formed on the retina of human eye. Obtain the focal length. Substitute 50 for p and 2.5 for q in equation (1), 1 f = 1 50 + 1 2 (b) To determine The rate of change of the focal length with respect to the distance of the object.

Applied Calculus for the Managerial, Life, and Social Sciences (MindTap Course List)

10th Edition

ISBN: 9781305657861

Author: Soo T. Tan

Publisher: Cengage Learning

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Ratios

A ratio is a comparison between two numbers of the same kind. It represents how many times one number contains another. It also represents how small or large one number is compared to the other.

Trigonometric Ratios

Trigonometric ratios give values of trigonometric functions. It always deals with triangles that have one angle measuring 90 degrees. These triangles are right-angled. We take the ratio of sides of these triangles.

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Question

Chapter 3.2, Problem 68E

(a)

To determine

The focal length of the cornea lens system.

(b)

To determine

The rate of change of the focal length with respect to the distance of the object.

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Chapter 3 Solutions

Applied Calculus for the Managerial, Life, and Social Sciences (MindTap Course List)

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The focal length of the cornea lens system.

Solution Summary: The author calculates the focal length of the cornea lens system. The distance between object location and retina is 50 cm.

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The focal length of the cornea lens system.

The rate of change of the focal length with respect to the distance of the object.

Chapter 3 Solutions