Superluminal jets. Figure 37-29 a shows the path taken by a knot in a jet of ionized gas that has been expelled from a galaxy. The knot travels at constant velocity v → at angle θ from the direction of Earth. The knot occasionally emits a burst of light, which is eventually detected on Earth. Two bursts are indicated in Fig. 37-29 a, separated by time t as measured in a stationary frame near the bursts. The bursts are shown in Fig. 37-29 b as if they were photographed on the same piece of film, first when light from burst 1 arrived on Earth and then later when light from burst 2 arrived. The apparent distance D app traveled by the knot between the two bursts is the distance across an Earth-observer’s view of the knot’s path. The apparent time T app between the bursts is the difference in the arrival times of the light from them. The apparent speed of the knot is then V app = D app /T app . In terms of v , t, and θ, what are (a) D app and (b) T app ? (c) Evaluate V app for v = 0.980 c and θ = 30.0°. When superluminal (faster than light) jets were first observed, they seemed to defy special relativity—at least until the correct geometry (Fig. 37-29 a ) was understood. Figure 37-29 Problem 63.
Superluminal jets. Figure 37-29 a shows the path taken by a knot in a jet of ionized gas that has been expelled from a galaxy. The knot travels at constant velocity v → at angle θ from the direction of Earth. The knot occasionally emits a burst of light, which is eventually detected on Earth. Two bursts are indicated in Fig. 37-29 a, separated by time t as measured in a stationary frame near the bursts. The bursts are shown in Fig. 37-29 b as if they were photographed on the same piece of film, first when light from burst 1 arrived on Earth and then later when light from burst 2 arrived. The apparent distance D app traveled by the knot between the two bursts is the distance across an Earth-observer’s view of the knot’s path. The apparent time T app between the bursts is the difference in the arrival times of the light from them. The apparent speed of the knot is then V app = D app /T app . In terms of v , t, and θ, what are (a) D app and (b) T app ? (c) Evaluate V app for v = 0.980 c and θ = 30.0°. When superluminal (faster than light) jets were first observed, they seemed to defy special relativity—at least until the correct geometry (Fig. 37-29 a ) was understood. Figure 37-29 Problem 63.
Superluminal jets. Figure 37-29a shows the path taken by a knot in a jet of ionized gas that has been expelled from a galaxy. The knot travels at constant velocity
v
→
at angle θ from the direction of Earth. The knot occasionally emits a burst of light, which is eventually detected on Earth. Two bursts are indicated in Fig. 37-29a, separated by time t as measured in a stationary frame near the bursts. The bursts are shown in Fig. 37-29b as if they were photographed on the same piece of film, first when light from burst 1 arrived on Earth and then later when light from burst 2 arrived. The apparent distance Dapp traveled by the knot between the two bursts is the distance across an Earth-observer’s view of the knot’s path. The apparent time Tapp between the bursts is the difference in the arrival times of the light from them. The apparent speed of the knot is then Vapp = Dapp/Tapp. In terms of v, t, and θ, what are (a) Dapp and (b) Tapp? (c) Evaluate Vapp for v = 0.980c and θ = 30.0°. When superluminal (faster than light) jets were first observed, they seemed to defy special relativity—at least until the correct geometry (Fig. 37-29a) was understood.
Checkpoint 4
The figure shows four orientations of an electric di-
pole in an external electric field. Rank the orienta-
tions according to (a) the magnitude of the torque
on the dipole and (b) the potential energy of the di-
pole, greatest first.
(1)
(2)
E
(4)
What is integrated science.
What is fractional distillation
What is simple distillation
19:39 ·
C
Chegg
1 69%
✓
The compound beam is fixed at Ę and supported by rollers at A and B. There are pins at C and D. Take
F=1700 lb. (Figure 1)
Figure
800 lb
||-5-
F
600 lb
بتا
D
E
C
BO
10 ft 5 ft 4 ft-—— 6 ft — 5 ft-
Solved Part A The compound
beam is fixed at E and...
Hình ảnh có thể có bản quyền. Tìm hiểu thêm
Problem
A-12
% Chia sẻ
kip
800 lb
Truy cập )
D Lưu
of
C
600 lb
|-sa+ 10ft 5ft 4ft6ft
D
E
5 ft-
Trying
Cheaa
Những kết quả này có
hữu ích không?
There are pins at C and D To F-1200 Egue!)
Chegg
Solved The compound b...
Có Không ☑
|||
Chegg
10
וח
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