
Concept explainers
(a)
The distance of the object from the mirror.
(a)

Answer to Problem 46PQ
The distance of the object from the mirror is
Explanation of Solution
Write the equation for the mirror.
Here,
Rewrite the above expression for
Write the equation for magnification produced by the mirror and find
Here,
Conclusion:
Substitute
Substitute
Therefore, the distance of the object from the mirror is
(b)
Whether the image formed by the mirror is real or virtual.
(b)

Answer to Problem 46PQ
The image distance from the mirror is negative, so the image formed by the mirror is virtual.
Explanation of Solution
Consider equation (III) for the image distance.
Conclusion:
Substitute
Therefore, the image formed at the distance of
(c)
A ray diagram for showing the locations of the object and image.
(c)

Answer to Problem 46PQ
Ray diagram of the object and the image location is shown in the following figure using three rays.
Explanation of Solution
Ray 1 will pass from the top of the object through the vertex of the mirror and reflected opposite to the object position.
Ray 2 will pass from the bottom of the object and reflected back from the mirror on itself.
Ray 3 will pass from the top of the object, which is parallel to the principle axis and reflected through the mirror from the focal point.
The image formed will be virtual and upright.
Therefore, the ray diagram of the object and the image location is shown in figure 1 using three rays.
Figure (1)
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Chapter 37 Solutions
EBK PHYSICS FOR SCIENTISTS AND ENGINEER
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