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Coherent light rays of wavelength λ strike a pair of slits separated by distance d at an angle θ1 with respect to the normal to the plane containing the slits as shown in Figure P36.9. The rays leaving the slits make an angle θ2 with respect to the normal, and an interference maximum is formed by those rays on a screen that is a great distance from the slits. Show that the angle θ2 is given by
where m is an integer.
Figure P36.9
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Chapter 37 Solutions
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- Table P35.80 presents data gathered by students performing a double-slit experiment. The distance between the slits is 0.0700 mm, and the distance to the screen is 2.50 m. The intensity of the central maximum is 6.50 106 W/m2. What is the intensity at y = 0.500 cm? TABLE P35.80arrow_forwardA Fraunhofer diffraction pattern is produced on a screen located 1.00 m from a single slit. If a light source of wavelength 5.00 107 m is used and the distance from the center of the central bright fringe to the first dark fringe is 5.00 103 m, what is the slit width? (a) 0.010 0 mm (b) 0.100 mm (c) 0.200 mm (d) 1.00 mm (e) 0.005 00 mmarrow_forwardThe figure shows the interference pattern that appears on a distant screen when coherent light is incident on a mask with two identical, very narrow slits. Points P and Q are maxima; Point R is a minimum. The wavelength of the light that created the interference pattern is λ=678nm, the two slites are separated by rm d=6 μm, and the distance from the slits to the center of the screen is L=80cm . The difference in path length at a point on the screen is Δs=|s1−s2|, where s1s1 and s2s2 are the distances from each slit to the point. What is ΔsΔs (in nm) at Point P? What is ΔsΔs (in nm) at Point Q? What is ΔsΔs (in nm) at Point R?arrow_forward
- White light is used to illuminate the two slits in a Young's double slit experiment. The separation between the slits is b and the screen is at a distance d (>> b) from the slits. At a point on the screen directly in front of one of the slits, certain wavelengths are missing. Some of these missing wavelengths are (a) λ = b²/d (b) λ = 2b²/d (d) λ = 2b²/3d (c) λ = b²/3d 2arrow_forwardA double-slit interference pattern is created by two narrow slits spaced 0.20 mm apart. The distance between the first and the fifth minimum on a screen 59 cm behind the slits is 6.5 mm. What is the wavelength (in nmnm) of the light used in this experiment?arrow_forwardIn a 2-slit experiment, one of the slits is covered by a thin film of refractive index n1 and the other slit is covered by another thin film of refractive index n2 (n1>n2). Both films have the same thickness t. A flat screen is located a distance L from the slits. The slit spacing is d. Find the shift in the position of the central maximum of the interference pattern because of the presence of the thin films.arrow_forward
- Consider a light wave passing through a slit and propagating toward a distant screen. Figure P37.53 shows the intensity variation for the pattern on the screen. Give a mathematical argument that more than 90% of the transmitted energy is in the central maximum of the diffraction pattern. Sugges- tion: You are not expected to calculate the precise percent- age, but explain the steps of your reasoning. You may use the identification 1 1 8 Imax asine -3T -27 -T 27 37 A Figure P37.53 ||arrow_forwardA two-slit Young’s interference experiment is arranged with the wavelength of the light source λ = 0.5 μm. When a thin film of transparent material is put in front of one of the slits, the zero order fringe moves to the position previously occupied by the 4th order bright fringe. The index of refraction of the film is n = 1.2. Calculate the thickness of the film.arrow_forward35. Figure P36.35 shows a radio-wave transmitter and a receiver separated by a distance d - 50.0 m and both a distance A - 35.0 m above the ground. The receiver can receive sig- nals both directly from the transmitter and indirectly from signals that reflect from the ground. Assume the ground is level between the transmitter and receiver and a 180° phase shift occurs upon reflection. Determine the longest wave- lengths that interfere (a) constructively and (b) destructively. Transmitter Recriver Figure P36.35 Problems 35 and 36.arrow_forward
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