EBK PHYSICS FOR SCIENTISTS AND ENGINEER
EBK PHYSICS FOR SCIENTISTS AND ENGINEER
6th Edition
ISBN: 9781319321710
Author: Mosca
Publisher: VST
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Chapter 36, Problem 75P

(a)

To determine

The Rydberg constant for tritium.

(b)

To determine

The difference of longest wavelength Balmer line of tritium and deuterium.

(c)

To determine

The difference of longest wavelength Balmer line of tritium and hydrogen.

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Three isotopes of hydrogen occur in nature; ordinary hydrogen, deuterium, and tritium. Their nuclei consist of, respectively, 1 proton, 1 proton and 1 neutron (deuteron), and 1 proton and 2 neutrons (triton). (a) Determine Rydberg constants for deuterium and tritium. (b) Determine the wavelength difference between the Balmer α lines of deuterium and tritium. (c) Determine the wavelength difference between the Balmer α lines of hydrogen and tritium. Note: The difference in this case would be caused by the nuclear mass. In deriving the Bohr atom, the first order of approximation was to assume that the nucleus doesn't move at all. The correction to this can be done by replacing the mass of the electron with the reduced mass of the electron-nucleus system, where, as you studied in mechanics, the reduced mass is given by μ=m1m2/(m1+m2). Additionally, the Balmer series is the one that terminates in the n=2 level with the α line corresponding to the n=3→n=2 transition.
where ?∞ = 1.097 × 10^7 m−1is the Rydberg constant and ? is the atomic number (thenumber of protons found in the nucleus). Calculate the ground state energy of a triplyionised beryllium atom, Be3+ (a beryllium atom with three electrons removed).
If, in 1 1 = Ry - you set ni = 1 and take n2 greater than 1, you generate what is known as the Lyman %3D series. Find the wavelength of the first mem- ber of this series. The value of ħ is 1.05457 × 10¬34 J.s; the Rydberg constant for hydrogen is 1.09735 × 10’ m¬'; the Bohr radius is 5.29177 × 10¬1" m; and the ground state energy for hydrogen is 13.6057 eV. Answer in units of nm. Consider the next three members of this se- ries. The wavelengths of successive members of the Lyman series approach a common limit as n2 → ∞. What is this limit? Answer in units of nm.
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