EBK PHYSICS FOR SCIENTISTS AND ENGINEER
EBK PHYSICS FOR SCIENTISTS AND ENGINEER
6th Edition
ISBN: 9781319321710
Author: Mosca
Publisher: VST
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Chapter 36, Problem 34P

(a)

To determine

The possible values of n and ml for the given orbital number.

(a)

Expert Solution
Check Mark

Answer to Problem 34P

The possible values of n is n4 and ml is 3,2,1,0,+1,+2,+3 .

Explanation of Solution

Given:

The orbital number is l=3 .

Formula used:

The expression to calculate the possible values of principal quantum number is given by,

  n=l+x,(xN)

Here x belongs to Natural number.

The expression to calculate the possible values of magnetic orbital quantum number is given by,

  m=x,(lnxln)

Here x is the integer.

Calculation:

The possible values of the principal quantum number is calculated as,

  n=3+x,(xN)

So, the possible value of the orbital numbers are 3,4,5,6... .

The possible values of n is n4 .

The possible values of the magnetic orbital quantum number for l=0 is calculated as,

  m=x,(0x0)

So, the possible value of the magnetic orbital numbers is 0 .

The possible values of the magnetic orbital quantum number for l=1 is calculated as,

  ml=x,(1x1)

So, the possible value of the magnetic orbital numbers is 1,0,1 .

The possible values of the magnetic orbital quantum number for l=2 is calculated as,

  ml=x,(2x2)

So, the possible value of the magnetic orbital numbers is 2,1,0,1,2 .

The possible values of the magnetic orbital quantum number for l=3 is calculated as,

  ml=x,(3x3)

So, the possible value of the magnetic orbital numbers is 3,2,1,0,1,2,3 .

Conclusion:

Therefore, the possible values of n is n4 and ml is 3,2,1,0,+1,+2,+3 .

(b)

To determine

The possible values of n and ml for the given orbital number.

(b)

Expert Solution
Check Mark

Answer to Problem 34P

The possible values of n is n5 and ml is 4,3,2,1,0,+1,+2,+3,+4 .

Explanation of Solution

Given:

The orbital number is l=4 .

Formula used:

The expression to calculate the possible values of principal quantum number is given by,

  n=l+x,(xN)

Here x belongs to Natural number.

The expression to calculate the possible values of magnetic orbital quantum number is given by,

  m=x,(lnxln)

Here x is the integer.

Calculation:

The possible values of the principal quantum number is calculated as,

  n=4+x,(xN)

So, the possible value of the orbital numbers are 5,6,7,8... .

The possible values of n is n5 .

The possible values of the magnetic orbital quantum number for l=0 is calculated as,

  m=x,(0x0)

So, the possible value of the magnetic orbital numbers is 0 .

The possible values of the magnetic orbital quantum number for l=1 is calculated as,

  ml=x,(1x1)

So, the possible value of the magnetic orbital numbers is 1,0,1 .

The possible values of the magnetic orbital quantum number for l=2 is calculated as,

  ml=x,(2x2)

So, the possible value of the magnetic orbital numbers is 2,1,0,1,2 .

The possible values of the magnetic orbital quantum number for l=3 is calculated as,

  ml=x,(3x3)

So, the possible value of the magnetic orbital numbers is 3,2,1,0,1,2,3 .

The possible values of the magnetic orbital quantum number for l=4 is calculated as,

  ml=x,(4x4)

So, the possible value of the magnetic orbital numbers is 4,3,2,1,0,1,2,3,4 .

Conclusion:

Therefore, the possible values of n is n5 and ml is 4,3,2,1,0,+1,+2,+3,+4 .

(c)

To determine

The possible values of n and ml for the given orbital number.

(c)

Expert Solution
Check Mark

Answer to Problem 34P

The possible values of n is n1 and ml is 0 .

Explanation of Solution

Given:

The orbital number is l=3 .

Formula used:

The expression to calculate the possible values of principal quantum number is given by,

  n=l+x,(xN)

Here x belongs to Natural number.

The expression to calculate the possible values of magnetic orbital quantum number is given by,

  m=x,(lnxln)

Here x is the integer.

Calculation:

The possible values of the principal quantum number is calculated as,

  n=0+x,(xN)

So, the possible value of the orbital numbers are 1,2,3... .

The possible values of n is n1 .

The possible values of the magnetic orbital quantum number for l=0 is calculated as,

  m=x,(0x0)

So, the possible value of the magnetic orbital numbers is 0 .

Conclusion:

Therefore, the possible values of n is n1 and ml is 0 .

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