Physics For Scientists And Engineers With Modern Physics, 9th Edition, The Ohio State University
9th Edition
ISBN: 9781305372337
Author: Raymond A. Serway | John W. Jewett
Publisher: Cengage Learning
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Chapter 36, Problem 65P
(a)
To determine
Whether a single pair of glasses can correct the patient vision.
(b)
To determine
The power needed to correct the near vision of patient
(c)
To determine
The power needed to correct the far vision of patient
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Chapter 36 Solutions
Physics For Scientists And Engineers With Modern Physics, 9th Edition, The Ohio State University
Ch. 36.1 - Prob. 36.1QQCh. 36.2 - You wish to start a fire by reflecting sunlight...Ch. 36.2 - Consider the image in the mirror in Figure 35.14....Ch. 36.3 - Prob. 36.4QQCh. 36.3 - Prob. 36.5QQCh. 36.4 - What is the focal length of a pane of window...Ch. 36.6 - Prob. 36.7QQCh. 36.7 - Prob. 36.8QQCh. 36 - Prob. 1OQCh. 36 - Prob. 2OQ
Ch. 36 - Prob. 3OQCh. 36 - Prob. 4OQCh. 36 - Prob. 5OQCh. 36 - Prob. 6OQCh. 36 - Prob. 7OQCh. 36 - Prob. 8OQCh. 36 - Prob. 9OQCh. 36 - Prob. 10OQCh. 36 - Prob. 11OQCh. 36 - Prob. 12OQCh. 36 - Prob. 13OQCh. 36 - Prob. 14OQCh. 36 - Prob. 1CQCh. 36 - Prob. 2CQCh. 36 - Prob. 3CQCh. 36 - Prob. 4CQCh. 36 - Prob. 5CQCh. 36 - Explain why a fish in a spherical goldfish bowl...Ch. 36 - Prob. 7CQCh. 36 - Prob. 8CQCh. 36 - Prob. 9CQCh. 36 - Prob. 10CQCh. 36 - Prob. 11CQCh. 36 - Prob. 12CQCh. 36 - Prob. 13CQCh. 36 - Prob. 14CQCh. 36 - Prob. 15CQCh. 36 - Prob. 16CQCh. 36 - Prob. 17CQCh. 36 - Prob. 1PCh. 36 - Prob. 2PCh. 36 - (a) Does your bathroom mirror show you older or...Ch. 36 - Prob. 4PCh. 36 - Prob. 5PCh. 36 - Two flat mirrors have their reflecting surfaces...Ch. 36 - Prob. 7PCh. 36 - Prob. 8PCh. 36 - Prob. 9PCh. 36 - Prob. 10PCh. 36 - A convex spherical mirror has a radius of...Ch. 36 - Prob. 12PCh. 36 - An object of height 2.00 cm is placed 30.0 cm from...Ch. 36 - Prob. 14PCh. 36 - Prob. 15PCh. 36 - Prob. 16PCh. 36 - Prob. 17PCh. 36 - Prob. 18PCh. 36 - (a) A concave spherical mirror forms an inverted...Ch. 36 - Prob. 20PCh. 36 - Prob. 21PCh. 36 - A concave spherical mirror has a radius of...Ch. 36 - Prob. 23PCh. 36 - Prob. 24PCh. 36 - Prob. 25PCh. 36 - Prob. 26PCh. 36 - Prob. 27PCh. 36 - Prob. 28PCh. 36 - One end of a long glass rod (n = 1.50) is formed...Ch. 36 - Prob. 30PCh. 36 - Prob. 31PCh. 36 - Prob. 32PCh. 36 - Prob. 33PCh. 36 - Prob. 34PCh. 36 - Prob. 35PCh. 36 - Prob. 36PCh. 36 - Prob. 37PCh. 36 - Prob. 38PCh. 36 - Prob. 39PCh. 36 - Prob. 40PCh. 36 - Prob. 41PCh. 36 - An objects distance from a converging lens is 5.00...Ch. 36 - Prob. 43PCh. 36 - Prob. 44PCh. 36 - A converging lens has a focal length of 10.0 cm....Ch. 36 - Prob. 46PCh. 36 - Prob. 47PCh. 36 - Prob. 48PCh. 36 - Prob. 49PCh. 36 - Prob. 50PCh. 36 - Prob. 51PCh. 36 - Prob. 52PCh. 36 - Prob. 53PCh. 36 - Prob. 54PCh. 36 - Prob. 55PCh. 36 - Prob. 56PCh. 36 - Prob. 57PCh. 36 - Prob. 58PCh. 36 - Prob. 59PCh. 36 - Prob. 60PCh. 36 - Prob. 61PCh. 36 - Prob. 62PCh. 36 - Prob. 63PCh. 36 - A simple model of the human eye ignores its lens...Ch. 36 - Prob. 65PCh. 36 - Prob. 66PCh. 36 - Prob. 67PCh. 36 - Prob. 68PCh. 36 - Prob. 69PCh. 36 - Prob. 70PCh. 36 - Prob. 71APCh. 36 - Prob. 72APCh. 36 - Prob. 73APCh. 36 - The distance between an object and its upright...Ch. 36 - Prob. 75APCh. 36 - Prob. 76APCh. 36 - Prob. 77APCh. 36 - Prob. 78APCh. 36 - Prob. 79APCh. 36 - Prob. 80APCh. 36 - Prob. 81APCh. 36 - In many applications, it is necessary to expand or...Ch. 36 - Prob. 83APCh. 36 - Prob. 84APCh. 36 - Two lenses made of kinds of glass having different...Ch. 36 - Prob. 86APCh. 36 - Prob. 87APCh. 36 - Prob. 88APCh. 36 - Prob. 89APCh. 36 - Prob. 90APCh. 36 - Prob. 91APCh. 36 - Prob. 92APCh. 36 - Prob. 93CPCh. 36 - A zoom lens system is a combination of lenses that...Ch. 36 - Prob. 95CPCh. 36 - Prob. 96CPCh. 36 - Prob. 97CP
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- It has become common to replace the cataract-clouded lens of the eye with an internal lens. This intraocular lens can be chosen so that the person has perfect distant vision. Will the person be able to read without glasses? If the person was nearsighted, is the power of the intraocular lens greater or less than the removed lens?arrow_forwardIn Figures CQ36.11a and CQ36.11b, which glasses correct nearsightedness and which correct farsightedness?arrow_forwardShow that the magnification of a thin lens is given by M = di/do (Eq. 38.6). Hint: Follow the derivation of the lens makers equation (page 1233) and start with a thick lens.arrow_forward
- A particular nearsighted patient cant see objects clearly beyond 15.0 cm from their eye. Determine (a) the lens power required to correct the patients vision and (b) the type of lens required (converging or diverging). Neglect the distance between the eye and the corrective lens.arrow_forwardA converging lens made of crown glass has a focal length of 15.0 cm when used in air. If the lens is immersed in water, what is its focal length? (a) negative (b) less than 15.0 cm (c) equal to 15.0 cm (d) greater than 15.0 cm (e) none of those answersarrow_forwardA converging lens has a focal length of 10.0 cm. Locate the object if a real image is located at a distance from the lens of (a) 20.0 cm and (b) 50.0 cm. What If? Redo the calculations if the images are virtual and located at a distance from the lens of (c) 20.0 cm and (d) 50.0 cm.arrow_forward
- Two thin lenses of focal lengths f1 = 15.0 and f2 = 10.0 cm, respectively, are separated by 35.0 cm along a common axis. The f1 lens is located to the left of the f2 lens. An object is now placed 50.0 cm to the left of the f1 lens, and a final image due to light passing though both lenses forms. By what factor is the final image different in size from the object? (a) 0.600 (b) 1.20 (c) 2.40 (d) 3.60 (e) none of those answersarrow_forwardA 7.5 binocular produces an angular magnification of —7.50, acting like a telescope. (Mirrors are used to make the image upright.) If the binoculars have objective lenses with a 75.0-cm focal length, what is the focal length of the eyepiece lenses?arrow_forwardIn Figure P26.38, a thin converging lens of focal length 14.0 cm forms an image of the square abcd, which is hc = hb = 10.0 cm high and lies between distances of pd = 20.0 cm and pa = 30.0 cm from the lens. Let a, b, c, and d represent the respective corners of the image. Let qa represent the image distance for points a and b, qd represent the image distance for points c and d, hb represent the distance from point b to the axis, and hc represent the height of c. (a) Find qa, qd, hb, and hc. (b) Make a sketch of the image. (c) The area of the object is 100 cm2. By carrying out the following steps, you will evaluate the area of the image. Let q represent the image distance of any point between a and d, for which the object distance is p. Let h represent the distance from the axis to the point at the edge of the image between b and c at image distance q. Demonstrate that h=10.0q(114.01q) where h and q are in centimeters. (d) Explain why the geometric area of the image is given by qaqdhdq (e) Carry out the integration to find the area of the image. Figure P26.38arrow_forward
- Figure P26.39 diagrams a cross-section of a camera. It has a single lens of focal length 65.0 mm, which is to form an image on the CCD (charge-coupled device) at the back of the camera. Suppose the position of the lens has been adjusted to focus the image of a distant object. How far and in what direction must the lens be moved to form a sharp image of an object that is 2.00 m away? Figure P26.39arrow_forwardA microscope has an objective lens with a focal length of 16.22 mm and an eyepiece with a focal length of 9.50 mm. With the length of the barrel set at 29.0 cm, the diameter of a red blood cells image subtends an angle of 1.43 mrad with the eye. It the final image distance is 29.0 cm from the eyepiece, what is the actual diameter of the red blood cell? Hint: To solve this question, go back to basics and use the thin-lens equation.arrow_forwardFor a normal, relaxed eye, a magnifying glass produces an angular magnification of 4.0. What is the largest magnification possible with this magnifying glass?arrow_forward
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Convex and Concave Lenses; Author: Manocha Academy;https://www.youtube.com/watch?v=CJ6aB5ULqa0;License: Standard YouTube License, CC-BY