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MindTap for Herman's Understanding Motor Controls, 4th Edition [Instant Access], 2 terms
4th Edition
ISBN: 9781337798754
Author: Herman; Stephen L.
Publisher: Cengage Learning US
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Chapter 36, Problem 5RQ
Why are SCRs used to construct a bridge rectifier in many solid-state variable frequency drives?
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11-5. Compute all the dimensional changes for the steel bar
when subjected to the loads shown. The proportional limit of the
steel is 230 MPa.
265 kN
100 mm
600 kN
25 mm thickness
X
Z
600 kN
450 mm
E=207×103 MPa; μ= 0.25
265 kN
T₁
F
Rd = 0.2 m
md =
2 kg
T₂
Tz1
Rc = 0.4 m
mc = 5 kg
m = 3 kg
Chapter 36 Solutions
MindTap for Herman's Understanding Motor Controls, 4th Edition [Instant Access], 2 terms
Ch. 36 - Prob. 1RQCh. 36 - Prob. 2RQCh. 36 - If an alternator is used to provide variable...Ch. 36 - What solid-state device is generally used to...Ch. 36 - Why are SCRs used to construct a bridge rectifier...Ch. 36 - What is the main disadvantage of using SCRs in a...Ch. 36 - How are junction transistors driven into...Ch. 36 - What is the disadvantage of driving a junction...Ch. 36 - Prob. 9RQCh. 36 - In variable frequency drives that employ IGBTs,...
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- Hello I was going over the solution for this probem and I'm a bit confused on the last part. Can you please explain to me 1^4 was used for the Co of the tubular cross section? Thank you!arrow_forwardBlood (HD = 0.45 in large diameter tubes) is forced through hollow fiber tubes that are 20 µm in diameter.Equating the volumetric flowrate expressions from (1) assuming marginal zone theory and (2) using an apparentviscosity for the blood, estimate the marginal zone thickness at this diameter. The viscosity of plasma is 1.2 cParrow_forwardQ2: Find the shear load on bolt A for the connection shown in Figure 2. Dimensions are in mm Fig. 2 24 0-0 0-0 A 180kN (10 Markarrow_forward
- determine the direction and magnitude of angular velocity ω3 of link CD in the four-bar linkage using the relative velocity graphical methodarrow_forwardFour-bar linkage mechanism, AB=40mm, BC=60mm, CD=70mm, AD=80mm, =60°, w1=10rad/s. Determine the direction and magnitude of w3 using relative motion graphical method. A B 2 3 77777 477777arrow_forwardFour-bar linkage mechanism, AB=40mm, BC=60mm, CD=70mm, AD=80mm, =60°, w1=10rad/s. Determine the direction and magnitude of w3 using relative motion graphical method. A B 2 3 77777 477777arrow_forward
- The evaporator of a vapor compression refrigeration cycle utilizing R-123 as the refrigerant isbeing used to chill water. The evaporator is a shell and tube heat exchanger with the water flowingthrough the tubes. The water enters the heat exchanger at a temperature of 54°F. The approachtemperature difference of the evaporator is 3°R. The evaporating pressure of the refrigeration cycleis 4.8 psia and the condensing pressure is 75 psia. The refrigerant is flowing through the cycle witha flow rate of 18,000 lbm/hr. The R-123 leaves the evaporator as a saturated vapor and leaves thecondenser as a saturated liquid. Determine the following:a. The outlet temperature of the chilled waterb. The volumetric flow rate of the chilled water (gpm)c. The UA product of the evaporator (Btu/h-°F)d. The heat transfer rate between the refrigerant and the water (tons)arrow_forward(Read image) (Answer given)arrow_forwardProblem (17): water flowing in an open channel of a rectangular cross-section with width (b) transitions from a mild slope to a steep slope (i.e., from subcritical to supercritical flow) with normal water depths of (y₁) and (y2), respectively. Given the values of y₁ [m], y₂ [m], and b [m], calculate the discharge in the channel (Q) in [Lit/s]. Givens: y1 = 4.112 m y2 = 0.387 m b = 0.942 m Answers: ( 1 ) 1880.186 lit/s ( 2 ) 4042.945 lit/s ( 3 ) 2553.11 lit/s ( 4 ) 3130.448 lit/sarrow_forward
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