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Comparing velocities Two stones are thrown vertically upward with matching initial velocities of 48 ft/s at time t = 0. One stone is thrown from the edge of a bridge that is 32 ft above the ground and the other stone is thrown from ground level. The height of the stone thrown from the bridge after t seconds is f(t) = −16t2 + 48t + 32, and the height of the stone thrown from the ground after t seconds is g(t) = −16t2 + 48t.
- a. Show that the stones reach their high points at the same time.
- b. How much higher does the stone thrown from the bridge go than the stone thrown from the ground?
- c. When do the stones strike the ground and with what velocities?
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