University Physics with Modern Physics, Volume 1 (Chs. 1-20) (14th Edition)

14th Edition

ISBN: 9780133978049

Author: Hugh D. Young, Roger A. Freedman

Publisher: PEARSON

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Textbook Question

Chapter 36, Problem 36.48P

CP A loudspeaker with a diaphragm that vibrates at 960 Hz is traveling at 80.0 m/s directly toward a pair of holes in a very large wall. The speed of sound in the region is 344 m/s. Far from the wall, you observe that the sound coming through the openings first cancels at ± 11.4° with respect to the direction in which the speaker is moving. (a) How far apart are the two openings? (b) At what angles would the sound first cancel it the source stopped moving?

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Chapter 36, Problem 36.47P

Chapter 36, Problem 36.49P

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Show that the units 1 v2/Q = 1 W, as implied by the equation P = V²/R. Starting with the equation P = V²/R, we can get an expression for a watt in terms of voltage and resistance. The units for voltage, V, are equivalent to [? v2 v2 A, are equivalent to J/C ✓ X . Therefore, 1 = 1 = 1 A V1 J/s Ω V-A X = 1 W. . The units for resistance, Q, are equivalent to ? The units for current,

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Chapter 36 Solutions

University Physics with Modern Physics, Volume 1 (Chs. 1-20) (14th Edition)

Ch. 36.1 - Can sound waves undergo diffraction around an...Ch. 36.2 - Rank the following single-slit diffraction...Ch. 36.3 - Coherent electromagnetic radiation is sent through...Ch. 36.4 - Suppose two slits, each of width a, are separated...Ch. 36.5 - What minimum number of slits would be required in...Ch. 36.6 - Prob. 36.6TYU Ch. 36.7 - Prob. 36.7TYU Ch. 36 - Why can we readily observe diffraction effects for...Ch. 36 - Prob. 36.2DQ Ch. 36 - You use a lens of diameter D and light of...

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