EBK WEBASSIGN FOR KATZ'S PHYSICS FOR SC
EBK WEBASSIGN FOR KATZ'S PHYSICS FOR SC
1st Edition
ISBN: 9781337684668
Author: Katz
Publisher: VST
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Chapter 36, Problem 30PQ

(a)

To determine

The half width of the spectral line.

(a)

Expert Solution
Check Mark

Answer to Problem 30PQ

The half width of the spectral line is 9.0×106rad.

Explanation of Solution

Write the expression for the grating spacing.

    d=1n                     (I)

Here, d is the grating spacing, n is the density of ruling.

Write the expression for the grating spacing in terms of number of ruling on the grating.

    d=lN                     (II)

Here, N is the number of ruling on the grating and l is the length of the grating.

Rewrite the equation (II) to determine N.

    N=ld                     (III)

Write the expression for the half width of the spectral line.

    Δθhw=λNdcosθ                            (IV)

Here, Δθhw is the half width of the spectral line λ is the wavelength of light used, d is the separation between rulings of grating and θ is the angle of diffraction corresponding to particular order maxima.

Conclusion:

Substitute 515rulings/mm for n in equation (I) to calculate d.

    d=1515rulings/mm=1.94×103mm(103m1mm)=1.94×106m

Substitute 5.00 cm for l and 1.94×106 m for d in equation (III) to calculate N.

    N=5.00cm(102m1 cm)1.94×106m=25733rulings

Substitute 25733 for N, 0° for θ, 450.0nm for λ and 1.94×106 m for d in equation (IV) to calculate Δθhw.

    Δθhw=450.0nm(109m1nm)(25733)(1.94×106m)(cos0°)=9×106rad

Therefore, the half width of the spectral line is 9.0×106rad.

(b)

To determine

The half width of the spectral line.

(b)

Expert Solution
Check Mark

Answer to Problem 30PQ

The half width of the spectral line is 1.30×105rad.

Explanation of Solution

Conclusion:

Substitute 25733 for N, 0° for θ, 650.0nm for λ and 1.94×106m for d in equation (IV) to calculate Δθhw.

    Δθhw=650.0nm(109m1 nm)(25733)(1.94×106m)(cos0°)=1.30×105rad

Therefore, the half width of the spectral line is 1.30×105rad.

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Chapter 36 Solutions

EBK WEBASSIGN FOR KATZ'S PHYSICS FOR SC

Ch. 36 - Prob. 6PQCh. 36 - Prob. 7PQCh. 36 - Prob. 8PQCh. 36 - Prob. 9PQCh. 36 - Prob. 10PQCh. 36 - Prob. 11PQCh. 36 - Prob. 12PQCh. 36 - Prob. 13PQCh. 36 - Prob. 14PQCh. 36 - Prob. 15PQCh. 36 - Prob. 16PQCh. 36 - Prob. 17PQCh. 36 - Prob. 18PQCh. 36 - Prob. 19PQCh. 36 - Prob. 20PQCh. 36 - Prob. 21PQCh. 36 - Prob. 22PQCh. 36 - Prob. 23PQCh. 36 - Prob. 24PQCh. 36 - Light of wavelength 566 nm is incident on a...Ch. 36 - Prob. 26PQCh. 36 - Prob. 27PQCh. 36 - Prob. 28PQCh. 36 - Prob. 29PQCh. 36 - Prob. 30PQCh. 36 - A light source emits a mixture of wavelengths from...Ch. 36 - Prob. 32PQCh. 36 - Prob. 33PQCh. 36 - Prob. 34PQCh. 36 - Prob. 35PQCh. 36 - Prob. 36PQCh. 36 - Prob. 37PQCh. 36 - Prob. 38PQCh. 36 - Prob. 39PQCh. 36 - Prob. 40PQCh. 36 - Prob. 41PQCh. 36 - Prob. 42PQCh. 36 - Prob. 43PQCh. 36 - Prob. 44PQCh. 36 - CASE STUDY Michelsons interferometer played an...Ch. 36 - CASE STUDY Michelsons interferometer played an...Ch. 36 - Prob. 47PQCh. 36 - Prob. 48PQCh. 36 - Problems 49 and 50 are paired. C Optical flats are...Ch. 36 - Optical flats are flat pieces of glass used to...Ch. 36 - Prob. 51PQCh. 36 - Prob. 52PQCh. 36 - Figure P36.53 shows two thin glass plates...Ch. 36 - Viewed from above, a thin film of motor oil with...Ch. 36 - Newtons rings, discovered by Isaac Newton, are an...Ch. 36 - Prob. 56PQCh. 36 - What is the radius of the beam of an argon laser...Ch. 36 - Prob. 58PQCh. 36 - A diffraction grating with 428 rulings per...Ch. 36 - How many rulings must a diffraction grating have...Ch. 36 - Prob. 61PQCh. 36 - White light is incident on a diffraction grating...Ch. 36 - X-rays incident on a crystal with planes of atoms...Ch. 36 - Prob. 64PQCh. 36 - Prob. 65PQCh. 36 - Prob. 66PQCh. 36 - The fringe width b is defined as the distance...Ch. 36 - The fringe width is defined as the distance...Ch. 36 - Prob. 69PQ
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