Explanation Given: The given equation is x 2 + y 2 = 13 at ( − 2 , 3 ) Concept Used: To find an equation of the tangent line to the graph of an equation y = f ( x ) at the a point ( a , b ) First find slope of the equation at the prescribed point as: m = d y d x | ( a , b ) Now, the equation of the tangent line to the graph of the equation is y = m x + c Put ( a , b ) coordinate in y = m x + c to find the value of c Calculation: To find an equation of the tangent line to the graph of x 2 + y 2 = 13 at ( − 2 , 3 ) First find slope of the equation at the prescribed point as: m = d y d x | ( a , b ) For that differentiate both side of the equation with respect to x as x 2 + y 2 = 13 d d x ( x 2 + y 2 ) = d d x ( 13 ) d d x x 2 + d d x y 2 = 0 Now, above can be simplified using chain rule of differentiation, as d d x x 2 <

Student's Solution and Survival Manual for Calculus

7th Edition

ISBN: 9781524934040

Author: STRAUSS MONTY J, TODA MAGDALENA DANIELE, SMITH KARL J

Publisher: Kendall Hunt Publishing

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Chapter 3.6, Problem 25PS

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Chapter 3.6, Problem 24PS

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Chapter 3 Solutions

Student's Solution and Survival Manual for Calculus

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Chapter 3 Solutions