Explanation Given: f ( x ) = x 5 − 3 x 3 − 5 x + 2 , where x = 1 Concept used: d ( x n ) d x = n ⋅ x n − 1 & d ( c ) d x = 0 , c ∈ R Equation of the tangent line passing through the point (a, b) with slope m is y − b = m ( x − a ) Calculation: Slope of the tangent is the derivative of the given function at the given point. So differentiating f(x) with respect to x, we get f ′ ( x ) = 5 x 4 − 3 ⋅ 3 x 2 − 5 ⋅ 1 + 0 = 5 x 4 − 9 x 2 − 5 Now slope of the tangent at x =1 is, f ′

Student's Solution and Survival Manual for Calculus

7th Edition

ISBN: 9781524934040

Author: STRAUSS MONTY J, TODA MAGDALENA DANIELE, SMITH KARL J

Publisher: Kendall Hunt Publishing

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Chapter 3.2, Problem 28PS

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To find the equation of the tangent line of the given function at the given point.

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Chapter 3.2, Problem 27PS

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Chapter 3 Solutions

Student's Solution and Survival Manual for Calculus

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To find the equation of the tangent line of the given function at the given point.

Solution Summary: The author explains the equation of the tangent line passing through the point (a, b) with slope m.

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Chapter 3 Solutions