Explanation Given information: A freshly brewed cup of coffee has temperature 95 ∘ C in a 20 ∘ C room. Calculation: Let T ( t ) be the temperature of the coffee after t minutes. The surrounding temperature is T s = 20 ∘ C . The initial temperature of the coffee is 95 ∘ C = T ( 0 ) Newton’s Law of cooling states that: d T d t = k ( T − 20 ) Now if we let y = T − 20 ; y ( 0 ) = T ( 0 ) − 20 = 95 − 20 = 75 ; so y satisfies d y d t = k y ; y ( 0 ) = 75 And by equation (2) we have: y ( t ) = y ( 0 ) e k t

Bundle: Biocalculus: Calculus, Probability, And Statistics For The Life Sciences + Webassign Printed Access Card For Stewart/day's Biocalculus: Calculus For Life Sciences, 1st Edition, Multi-term

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Chapter 3.6, Problem 16E

To determine

To find: time when its temperature is 70∘C , it is cooling at a rate of 1∘C per minute.

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Chapter 3.6, Problem 15E

Chapter 3.6, Problem 17E

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Bundle: Biocalculus: Calculus, Probability, And Statistics For The Life Sciences + Webassign Printed Access Card For Stewart/day's Biocalculus: Calculus For Life Sciences, 1st Edition, Multi-term

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time when its temperature is 70 ∘ C , it is cooling at a rate of 1 ∘ C per minute.

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To find: time when its temperature is 70∘C , it is cooling at a rate of 1∘C per minute.

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