Explanation Given: The function, y = sin x + sin 2 x and the point ( 0 , 0 ) Concept Used: Slope of the tangent line of a function f ( x ) at any point x = c is given by the first derivative at that point. That is the slope of tangent line at x = c is given by f ′ ( c ) . The point-slope form of the line passing through the point ( x 1 , y 1 ) and having slope m is given by y − y 1 = m ( x − x 1 ) . Power rule of derivatives, d d x ( x n ) = n x n − 1 Chain rule, d d x ( f ( g ( x ) ) ) = f ' ( g ( x ) ) ⋅ g ' ( x ) Derivative of any constant C is zero, that is, d d x ( C ) = 0 d d x ( sin x ) = cos x Calculation: Consider the function, y = sin x + sin 2 x In order to find the equation of tangent line, first find the slope of tangent line by finding the first derivative at the specified point

Bundle: Biocalculus: Calculus, Probability, And Statistics For The Life Sciences + Webassign Printed Access Card For Stewart/day's Biocalculus: Calculus For Life Sciences, 1st Edition, Multi-term

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ISBN: 9781305779037

Author: James Stewart, Troy Day

Publisher: Cengage Learning

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Chapter 3.5, Problem 44E

To determine

The equation of the tangent lineto the curve y=sinx+sin2x at the point (0,0) .

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Chapter 3.5, Problem 43E

Chapter 3.5, Problem 45E

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Chapter 3 Solutions

Bundle: Biocalculus: Calculus, Probability, And Statistics For The Life Sciences + Webassign Printed Access Card For Stewart/day's Biocalculus: Calculus For Life Sciences, 1st Edition, Multi-term

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The equation of the tangent lineto the curve y = sin x + sin 2 x at the point ( 0 , 0 ) .

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The equation of the tangent lineto the curve y=sinx+sin2x at the point (0,0) .

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