Fundamentals of Physics Extended 10E WileyPlus 5 Student Package

1st Edition

ISBN: 9781118441497

Author: Halliday

Publisher: John Wiley & Sons Inc (US)

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Chapter 36, Problem 15P

SSM WWW The full width at half-maximum (FWHM) of a central diffraction maximum is defined as the angle between the two points in the pattern where the intensity is one-half that at the center of the pattern. (See Fig. 36-8b.) (a) Show that the intensity drops to one-half the maximum value when sin² α = α²/2. (b) Verify that α = 1.39 rad (about 80°) is a solution to the transcendental equation of (a) (c) Show that the FWHM is ∆θ = 2 sin^–1(0.443λ/a), where a is the slit width. Calculate the FWHM of the central maximum for slit width (d) 1.00λ, (e) 5.00λ, and (f) 10.0λ.

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Chapter 36, Problem 14P

Chapter 36, Problem 16P

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Chapter 36 Solutions

Fundamentals of Physics Extended 10E WileyPlus 5 Student Package

Ch. 36 - You are conducting a single-slit diffraction...Ch. 36 - In a single-slit diffraction experiment, the top...Ch. 36 - For three experiments, Fig. 36-30 gives the...Ch. 36 - For three experiments, Fig. 36-31 gives versus...Ch. 36 - Figure 36-32 shows four choices for the...Ch. 36 - Prob. 6Q Ch. 36 - At night many people see rings called entoptic...Ch. 36 - a For a given diffraction grating, does the...Ch. 36 - Figure 36-33 shows a red line and a green line of...Ch. 36 - For the situation of Question 9 and Fig. 36-33, if...

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