Explanation 1) Concept: Using Bragg’s law and the given condition, we can find the angle θ . Then, by studying F i g . 36 - 28 , we can find the angle between the incident and scattered beams. 2) Formulas: i) From E q . 36 - 34 , Bragg’s law gives 2 d s i n θ = m λ ii) From F i g . 36 - 28 , the angle θ ' between the incident and scattered beams is θ ' = 180 ° - 2 θ 3) Given: i) The range of x ray wavelengths is from 0.120 n m to 0.0700 n m . ii) The plane separation is d = 0.25 n m iii) The scattered beams are produced for λ = 0.10 n m and λ ' = 0.075 n m . 4) Calculations: From E q . 36 - 34 , Bragg’s law gives 2 d s i n θ = m λ But, for λ = 0.10 n m , we have scattering for order m , and for λ ' = 0.075 n m , we have scattering for order m ' . Therefore, we must require m λ = m ' λ ' For given values of λ a n d λ ' , this suggests that m = 3 and m ' = 4

Fundamentals of Physics Extended 10E WileyPlus 5 Student Package

1st Edition

ISBN: 9781118441497

Author: Halliday

Publisher: John Wiley & Sons Inc (US)

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Chapter 36, Problem 104P

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Angle between the incident and scattered beams

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Chapter 36, Problem 103P

Chapter 36, Problem 105P

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Chapter 36 Solutions

Fundamentals of Physics Extended 10E WileyPlus 5 Student Package

Ch. 36 - You are conducting a single-slit diffraction...Ch. 36 - In a single-slit diffraction experiment, the top...Ch. 36 - For three experiments, Fig. 36-30 gives the...Ch. 36 - For three experiments, Fig. 36-31 gives versus...Ch. 36 - Figure 36-32 shows four choices for the...Ch. 36 - Prob. 6Q Ch. 36 - At night many people see rings called entoptic...Ch. 36 - a For a given diffraction grating, does the...Ch. 36 - Figure 36-33 shows a red line and a green line of...Ch. 36 - For the situation of Question 9 and Fig. 36-33, if...

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Angle between the incident and scattered beams

Solution Summary: The author explains how to find the angle between the incident and scattered beams using Bragg's law and the given condition.

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To find: Angle between the incident and scattered beams

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Chapter 36 Solutions

To find:

Angle between the incident and scattered beams