EBK AUTOMOTIVE TECHNOLOGY: A SYSTEMS AP
EBK AUTOMOTIVE TECHNOLOGY: A SYSTEMS AP
6th Edition
ISBN: 8220100474392
Author: ERJAVEC
Publisher: Cengage Learning US
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Chapter 36, Problem 10ASRQ

While discussing hydrogen: Technician A says that a hydrogen atom has one proton and two electrons. Technician B says that hydrogen is produced in a fuel cell when water is broken down into its basic elements. Who is correct?

a. Technician A only

b. Technician B only

c. Both A and B

d. Neither A nor B

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A triangular distributed load of max intensity w acts on beam AB. The beam is supported by a pin at A and member CD, which is connected by pins at C and D respectively. Determine the largest load intensity, Wmax, that can be applied if the pin at D can support a maximum force of 18000 N. Also determine the reactions at A and C and express each answer in Cartesian components. Assume the masses of both beam and member ✓ are negligible. Dwas шал = A BY NC SA 2016 Eric Davishahl C D -a- Ур -b- X B W Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Variable Value a 6.6 m b 11.88 m C 4.29 m The maximum load intensity is = wmax N/m. The reaction at A is A = The reaction at C is = i+ Ĵ N. ĴN. 12 i+
The beam is supported by a pin at B and a roller at C and is subjected to the loading shown with w =110 lb/ft, and F 205 lb. a.) If M = 2,590 ft-lb, determine the support reactions at B and C. Report your answers in both Cartesian components. b.) Determine the largest magnitude of the applied couple M for which the beam is still properly supported in equilibrium with the pin and roller as shown. 2013 Michael Swanbom CC BY NC SA M ру W B⚫ C F ka b Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Variable Value a 3.2 ft b 6.4 ft C 3 ft a.) The reaction at B is B = The reaction at C is C = ĵ lb. i+ Ĵ lb. b.) The largest couple that can be applied is M ft-lb. == i+

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EBK AUTOMOTIVE TECHNOLOGY: A SYSTEMS AP

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Extent of Reaction; Author: LearnChemE;https://www.youtube.com/watch?v=__stMf3OLP4;License: Standard Youtube License