Sunlight is absorbed in water, and as a result the light intensity in oceans, lakes, and ponds decreases exponentially with depth. The percentage of visible light, P (in decimal form). at a depth of x meters is given by P = e − k x , where k Is a constant related to the clarity and other physical properties of the water. The graph shows models for the open ocean. Lake Tahoe, and Lake Erie for data taken under similar conditions. Use these models for Exercises 73-76. Determine the depth at which the light intensity is 20 % of the value from the surface for each body of water given. Round to the nearest tenth of a meter.
Sunlight is absorbed in water, and as a result the light intensity in oceans, lakes, and ponds decreases exponentially with depth. The percentage of visible light, P (in decimal form). at a depth of x meters is given by P = e − k x , where k Is a constant related to the clarity and other physical properties of the water. The graph shows models for the open ocean. Lake Tahoe, and Lake Erie for data taken under similar conditions. Use these models for Exercises 73-76. Determine the depth at which the light intensity is 20 % of the value from the surface for each body of water given. Round to the nearest tenth of a meter.
Solution Summary: The author calculates the percentage of visible light in terms of depth from the surface for ocean, Lake Tahoe, and Erie.
Sunlight is absorbed in water, and as a result the light intensity in oceans, lakes, and ponds decreases exponentially with depth. The percentage of visible light, P (in decimal form). at a depth of x meters is given by
P
=
e
−
k
x
,
where k Is a constant related to the clarity and other physical properties of the water. The graph shows models for the open ocean. Lake Tahoe, and Lake Erie for data taken under similar conditions. Use these models for Exercises 73-76.
Determine the depth at which the light intensity is
20
%
of the value from the surface for each body of water given. Round to the nearest tenth of a meter.
Given lim x-4 f (x) = 1,limx-49 (x) = 10, and lim→-4 h (x) = -7 use the limit properties
to find lim→-4
1
[2h (x) — h(x) + 7 f(x)] :
-
h(x)+7f(x)
3
O DNE
17. Suppose we know that the graph below is the graph of a solution to dy/dt = f(t).
(a) How much of the slope field can
you sketch from this information?
[Hint: Note that the differential
equation depends only on t.]
(b) What can you say about the solu-
tion with y(0) = 2? (For example,
can you sketch the graph of this so-
lution?)
y(0) = 1
y
AN
(b) Find the (instantaneous) rate of change of y at x = 5.
In the previous part, we found the average rate of change for several intervals of decreasing size starting at x = 5. The instantaneous rate of
change of fat x = 5 is the limit of the average rate of change over the interval [x, x + h] as h approaches 0. This is given by the derivative in the
following limit.
lim
h→0
-
f(x + h) − f(x)
h
The first step to find this limit is to compute f(x + h). Recall that this means replacing the input variable x with the expression x + h in the rule
defining f.
f(x + h) = (x + h)² - 5(x+ h)
=
2xh+h2_
x² + 2xh + h² 5✔
-
5
)x - 5h
Step 4
-
The second step for finding the derivative of fat x is to find the difference f(x + h) − f(x).
-
f(x + h) f(x) =
= (x²
x² + 2xh + h² -
])-
=
2x
+ h² - 5h
])x-5h) - (x² - 5x)
=
]) (2x + h - 5)
Macbook Pro
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