The atmospheric pressure on an object decreases as altitude increases. If a is the height (in km) above sea heel, then the pressure P a (in mmHg) is approximated by P a = 760 e − 0.13 a . a. Find the atmospheric pressure at sea level. b. Determine the atmospheric pressure at 8.848 km (the altitude of Mt. Everest). Round to the nearest whole unit.
The atmospheric pressure on an object decreases as altitude increases. If a is the height (in km) above sea heel, then the pressure P a (in mmHg) is approximated by P a = 760 e − 0.13 a . a. Find the atmospheric pressure at sea level. b. Determine the atmospheric pressure at 8.848 km (the altitude of Mt. Everest). Round to the nearest whole unit.
The atmospheric pressure on an object decreases as altitude increases. If a is the height (in km) above sea heel, then the pressure
P
a
(in mmHg) is approximated by
P
a
=
760
e
−
0.13
a
.
a. Find the atmospheric pressure at sea level.
b. Determine the atmospheric pressure at 8.848 km (the altitude of Mt. Everest). Round to the nearest whole unit.
Write the given third order linear equation as an equivalent system of first order equations with initial values.
Use
Y1 = Y, Y2 = y', and y3 = y".
-
-
√ (3t¹ + 3 − t³)y" — y" + (3t² + 3)y' + (3t — 3t¹) y = 1 − 3t²
\y(3) = 1, y′(3) = −2, y″(3) = −3
(8) - (888) -
with initial values
Y
=
If you don't get this in 3 tries, you can get a hint.
Question 2
1 pts
Let A be the value of the triple integral
SSS.
(x³ y² z) dV where D is the region
D
bounded by the planes 3z + 5y = 15, 4z — 5y = 20, x = 0, x = 1, and z = 0.
Then the value of sin(3A) is
-0.003
0.496
-0.408
-0.420
0.384
-0.162
0.367
0.364
Question 1
Let A be the value of the triple integral SSS₂ (x + 22)
=
1 pts
dV where D is the
region in
0, y = 2, y = 2x, z = 0, and
the first octant bounded by the planes x
z = 1 + 2x + y. Then the value of cos(A/4) is
-0.411
0.709
0.067
-0.841
0.578
-0.913
-0.908
-0.120
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