Chapter 3.5, Problem 73ES

Suppose that the time $T$ (in days) for a cancerous tumor to double in volume $\left({\text{in cm}}^{\text{3}}\right)$ is given by

$T=\frac{10\ln 2}{\ln V_1-\ln V_0}\left(V_0<V_1\right)$

where $V_0$ is the volume of the tumor when it’s first observed and $V_1$ denotes its volume 10 days later. Assume that $V_0$ is correctly measured to be $20{\text{ cm}}^3$ and $V_1$ is measured to be $33{\text{ cm}}^{\text{3}}$ with a measurement error of at most $\pm 0.4{\text{ cm}}^{\text{3}}$ . Estimate the error in the computed value of $T$ .