Challenge Problem Removing a Discontinuity In Example 5 we graphed the rational function R ( x ) = 2 x 2 − 5 x + 2 x 2 − 4 and found that the graph has a hole at the point ( 2 , 3 4 ) . Therefore, the graph of R is discontinuous at ( 2 , 3 4 ) . We can remove this discontinuity by defining the rational function R using the following piecewise-defined function: R ( x ) = { 2 x 2 − 5 x + 2 x 2 − 4 if x ≠ 2 3 4 if x = 2 Redefine R from Problem 33 so that the discontinuity at x = 3 is removed. Redefine R from Problem 33 so that the discontinuity at x = 3 2 is removed. R ( x ) = x 2 + x − 12 x 2 − x − 6
Challenge Problem Removing a Discontinuity In Example 5 we graphed the rational function R ( x ) = 2 x 2 − 5 x + 2 x 2 − 4 and found that the graph has a hole at the point ( 2 , 3 4 ) . Therefore, the graph of R is discontinuous at ( 2 , 3 4 ) . We can remove this discontinuity by defining the rational function R using the following piecewise-defined function: R ( x ) = { 2 x 2 − 5 x + 2 x 2 − 4 if x ≠ 2 3 4 if x = 2 Redefine R from Problem 33 so that the discontinuity at x = 3 is removed. Redefine R from Problem 33 so that the discontinuity at x = 3 2 is removed. R ( x ) = x 2 + x − 12 x 2 − x − 6
Solution Summary: The author explains how to remove discontinuity at x=3 by redefining the function R(x).
Challenge Problem Removing a Discontinuity In Example
5
we graphed the rational function
R
(
x
)
=
2
x
2
−
5
x
+
2
x
2
−
4
and found that the graph has a hole at the point
(
2
,
3
4
)
. Therefore, the graph of
R
is discontinuous at
(
2
,
3
4
)
. We can remove this discontinuity by defining the rational function
R
using the following piecewise-defined function:
R
(
x
)
=
{
2
x
2
−
5
x
+
2
x
2
−
4
if
x
≠
2
3
4
if
x
=
2
Redefine
R
from Problem
33
so that the discontinuity at
x
=
3
is removed.
Redefine
R
from Problem
33
so that the discontinuity at
x
=
3
2
is removed.
1. For each of the following, find the critical numbers of f, the intervals on which f is increasing or decreasing, and the relative
maximum and minimum values of f.
(a) f(x) = x² - 2x²+3
(b) f(x) = (x+1)5-5x-2
(c) f(x) =
x2
x-9
2. For each of the following, find the intervals on which f is concave upward or downward and the inflection points of f.
(a) f(x) = x - 2x²+3
(b) g(x) = x³- x
(c) f(x)=x-6x3 + x-8
3. Find the relative maximum and minimum values of the following functions by using the Second Derivative Test.
(a) f(x)=1+3x² - 2x3
(b) g(x) = 2x3 + 3x² - 12x-4
Find the
Soultion to the following dy
differential equation using Fourier in
transforms:
=
, хуо, ухо
according to the terms:
lim u(x,y) = 0
x18
lim 4x (x,y) = 0
x14
2
u (x, 0) =
=\u(o,y) =
-y
لو
Chapter 3 Solutions
Pearson eText for Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry -- Instant Access (Pearson+)
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