Gravity. Refer to Problem 62. Find d F d r and discuss the connection between d F d r and d r d F . 62 . Gravity. The equation F = G m 1 m 2 r 2 is Newton’s law of universal gravitation. G is a constant and F is the gravitational force between two objects, having masses, m 1 and m 2 that are a distance r from each other. Use implicit differentiation to find d r d F . Assume that m 1 and m 2 are constant.
Gravity. Refer to Problem 62. Find d F d r and discuss the connection between d F d r and d r d F . 62 . Gravity. The equation F = G m 1 m 2 r 2 is Newton’s law of universal gravitation. G is a constant and F is the gravitational force between two objects, having masses, m 1 and m 2 that are a distance r from each other. Use implicit differentiation to find d r d F . Assume that m 1 and m 2 are constant.
Solution Summary: The author analyzes the Newton's law of universal gravitation and the connection between the two.
Gravity. Refer to Problem 62. Find
d
F
d
r
and discuss the connection between
d
F
d
r
and
d
r
d
F
.
62. Gravity. The equation
F
=
G
m
1
m
2
r
2
is Newton’s law of universal gravitation. G is a constant and F is the gravitational force between two objects, having masses, m1 and m2 that are a distance r from each other.
Use implicit differentiation to find
d
r
d
F
. Assume that m1 and m2 are constant.
20.
X
21 27
45
x
X =
X =
22. Find the sine, cosine, and tangent of a
10. An airplane flying 390 feet per second at an altitude of 5000 feet flew directly over an observer. The
image shows the relationship of the airplane to the observer at a
later time.
a.) Find an equation relating x and y.
5000°t 390
5000
b.) Find the value of x when y is 6,250.
Observer
c.) How fast is the distance from the observer to the airplane changing at the time when the airplane is
dy
at the time when
dt
dx
= 390 and y = 6,250?
dt
6,250 feet from the observer? That is, what is
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