University Physics with Modern Physics, Volume 1 (Chs. 1-20) and Mastering Physics with Pearson eText & ValuePack Access Card (14th Edition)
14th Edition
ISBN: 9780134209586
Author: Hugh D. Young
Publisher: PEARSON
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Chapter 35, Problem 35.38P
BIO Sensitive Eyes. After an eye examination, you put some eyedrops on your sensitive eyes. The cornea (the front part of the eye) has an index of refraction of 1.38. while the eyedrops have a refractive index of 1.45. After you put in the drops, your friends notice that your eyes look red, because red
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Chapter 35 Solutions
University Physics with Modern Physics, Volume 1 (Chs. 1-20) and Mastering Physics with Pearson eText & ValuePack Access Card (14th Edition)
Ch. 35.1 - Consider a point in Fig. 35.3 on the positive...Ch. 35.2 - You shine a tunable laser (whose wavelength can be...Ch. 35.3 - A two-slit interference experiment uses coherent...Ch. 35.4 - A thin layer of benzene (n = 1.501) lies on top of...Ch. 35.5 - You are observing the pattern of fringes in a...Ch. 35 - A two-slit interference experiment is set up, and...Ch. 35 - Could an experiment similar to Youngs two-slit...Ch. 35 - Monochromatic coherent light passing through two...Ch. 35 - In a two-slit interference pattern on a distant...Ch. 35 - Would the headlights of a distant car form a...
Ch. 35 - The two sources S1 and S2 shown in Fig. 35.3 emit...Ch. 35 - Could the Young two-slit interference experiment...Ch. 35 - Coherent red light illuminates two narrow slits...Ch. 35 - Coherent light with wavelength falls on two...Ch. 35 - Prob. 35.10DQCh. 35 - If the monochromatic light shown in Fig. 35.5a...Ch. 35 - In using the superposition principle to calculate...Ch. 35 - Prob. 35.13DQCh. 35 - A very thin soap film (n = 1.33), whose thickness...Ch. 35 - Interference can occur in thin films. Why is it...Ch. 35 - If we shine while light on an air wedge like that...Ch. 35 - Prob. 35.17DQCh. 35 - When a thin oil film spreads out on a puddle of...Ch. 35 - Section 35.1 Interference and Coherent Sources...Ch. 35 - Two speakers that are 15.0 m apart produce...Ch. 35 - A radio transmitting station operating at a...Ch. 35 - Radio Interference. Two radio antennas A and B...Ch. 35 - Prob. 35.5ECh. 35 - Two light sources can be adjusted to emit...Ch. 35 - Section 35.2 Two-Source Interference of Light...Ch. 35 - Coherent light with wavelength 450 nm falls on a...Ch. 35 - Two slits spaced 0.450 mm apart are placed 75.0 cm...Ch. 35 - If the entire apparatus of Exercise 35.9 (slits,...Ch. 35 - Two thin parallel slits that are 0.0116 mm apart...Ch. 35 - Coherent light with wavelength 400 nm passes...Ch. 35 - Two very narrow slits are spaced 1.80 m apart and...Ch. 35 - Coherent light that contains two wavelengths. 660...Ch. 35 - Coherent light with wavelength 600 nm passes...Ch. 35 - Coherent light of frequency 6.32 1014 Hz passes...Ch. 35 - In a two-slit interference pattern, the intensity...Ch. 35 - Coherent sources A and B emit electromagnetic...Ch. 35 - Coherent light with wavelength 500 nm passes...Ch. 35 - Two slits spaced 0.260 mm apart are 0.900 m from a...Ch. 35 - Consider two antennas separated by 9.00 m that...Ch. 35 - Two slits spaced 0.0720 mm apart are 0.800 m from...Ch. 35 - What is the thinnest film of a coating with n =...Ch. 35 - Nonglare Glass. When viewing a piece of art that...Ch. 35 - Two rectangular pieces of plane glass are laid one...Ch. 35 - A place of glass 9.00 cm long is placed in contact...Ch. 35 - A uniform film of TiO2, 1036 nm thick and having...Ch. 35 - A plastic film with index of refraction 1.70 is...Ch. 35 - The walls of a soap bubble have about the same...Ch. 35 - A researcher measures the thickness of a layer of...Ch. 35 - Prob. 35.31ECh. 35 - What is the thinnest soap film (excluding the case...Ch. 35 - How far must the mirror M2 (see Fig. 35.19) of the...Ch. 35 - Jan first uses a Michelson interferometer with the...Ch. 35 - One round face of a 3.25-m, solid, cylindrical...Ch. 35 - Newtons rings are visible when a planoconvex lens...Ch. 35 - BIO Coating Eyeglass Lenses. Eyeglass lenses can...Ch. 35 - BIO Sensitive Eyes. After an eye examination, you...Ch. 35 - Two flat plates of glass with parallel faces are...Ch. 35 - In a setup similar to that of Problem 35.39, the...Ch. 35 - Suppose you illuminate two thin slits by...Ch. 35 - CP CALC A very thin sheet of brass contains two...Ch. 35 - Two radio antennas radiating in phase are located...Ch. 35 - Prob. 35.44PCh. 35 - CP A thin uniform film of refractive index 1.750...Ch. 35 - GPS Transmission. The GPS (Global Positioning...Ch. 35 - White light reflects at normal incidence from the...Ch. 35 - Laser light of wavelength 510 nm is traveling in...Ch. 35 - Red light with wavelength 700 nm is passed through...Ch. 35 - BIO Reflective Coatings and Herring. Herring and...Ch. 35 - After a laser beam passes through two thin...Ch. 35 - DATA In your summer job at an optics company, you...Ch. 35 - DATA Short-wave radio antennas A and B are...Ch. 35 - DATA In your research lab, a very thin, flat piece...Ch. 35 - CP The index of refraction of a glass rod is 1.48...Ch. 35 - CP Figure P35.56 shows an interferometer known as...Ch. 35 - INTERFERENCE AND SOUND WAVES. Interference occurs...Ch. 35 - The professor returns the apparatus to the...Ch. 35 - The professor again returns the apparatus to its...Ch. 35 - The professor once again returns the apparatus to...
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- I need help with part B. I cant seem to get the correct answer. Please walk me through what youre doing to get to the answer and what that could bearrow_forwardQuestion 6: Chlorine is widely used to purify municipal water supplies and to treat swimming pool waters. Suppose that the volume of a particular sample of Cl₂ gas is 8.70 L at 895 torr and 24°C. (a) How many grams of Cl₂ are in the sample? ⚫ Atomic mass of CI = 35.453 g/mol • Molar mass of Cl₂ = 2 x 35.453 = 70.906 g/mol Solution: Use the Ideal Gas Law: Step 1: Convert Given Values • Pressure: P = 895 torr → atm PV= = nRT 1 P = 895 × = 1.1789 atm 760 • Temperature: Convert to Kelvin: T24273.15 = 297.15 K • Gas constant: R = 0.0821 L atm/mol. K Volume: V = 8.70 L Step 2: Solve for n . PV n = RT n = (1.1789)(8.70) (0.0821)(297.15) 10.25 n = = 0.420 mol 24.405 Step 3: Calculate Mass of Cl₂ Final Answer: 29.78 g of Cl₂. mass nx M mass= (0.420)(70.906) mass= 29.78 garrow_forwardE1 R₁ w 0.50 20 Ω 12 R₁₂ ww ΒΩ R₂ 60 E3 C RA w 15 Ω E2 0.25 E4 0.75 Ω 0.5 Ωarrow_forward
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Spectra Interference: Crash Course Physics #40; Author: CrashCourse;https://www.youtube.com/watch?v=-ob7foUzXaY;License: Standard YouTube License, CC-BY