Chapter 3.5, Problem 24P

Suppose $U=\{0,2,4,6,8,10\}$ is the universal set and $A=\{2,4,6\}.$

What is $A^{\prime }?$

To determine

To find: $A^{\prime }$ for universal set $U=\left\{0,2,4,6,8,10\right\}$ and set $A=\left\{2,4,6\right\}$ .

Answer to Problem 24P

  $A^{\prime }=\left\{0,8,10\right\}$

Explanation of Solution

Given:

The universal set and set are $U=\left\{0,2,4,6,8,10\right\}$ and $A=\left\{2,4,6\right\}$ .

Calculation:

A not $\left(A^{\prime }\right)$ is the set which has elements apart from A from universal set. 0, 8 and 10 are the elements of universal set that is not elements of set A .

Thus, $\left(A^{\prime }\right)$ is,

  $A^{\prime }=\left\{0,8,10\right\}$