Chapter 35, Problem 14SP

An ammeter in a 60.0-Hz circuit reads 2.50 A. Determine the maximum current in the circuit. [Hint: Study Eqs. (35.3) and (35.4).]

To determine

Themaximum current in the circuit if an ammeter in a $60.0\text{Hz}$ circuit reads $2.50\text{A}$.

Answer to Problem 14SP

Solution:

$\text{3}\text{.54 A}$

Explanation of Solution

Given data:

The rms value of current is $2.50\text{ A}$.

Formula used:

The expression that shows the relation between rms and the maximum value of current is expressed as,

$I_{rms}=\frac{i_0}{\sqrt{2}}$

Here, $I_{rms}$ is the rmsvalue of current in Ampere, and $i_0$ is the maximumvalue of current in Ampere.

Explanation:

Consider the expression that shows the relation between rms and the maximum value

$I_{rms}=\frac{i_0}{\sqrt{2}}$

Solve for $i_0$

$i_0=I_{rms}\sqrt{2}$

Substitute $2.50\text{ A}$ for $I_{rms}$

$\begin{array}{c}{i}_0=\left(2.50\text{ A}\right)\sqrt{2}\\ =3.54\text{ A}\end{array}$

Conclusion:

The maximum current in the circuit is $\text{3}\text{.54 A}$.