Explanation Given: Function y = sin ( x 2 ) . Formula Used: Formula of derivatives are as follows: d d x ( f ( u ) ) = d d u ( f ( u ) ) × d u d x , chain rule d d x ( x n ) = n x n − 1 d d x c . f ( x ) = c . d d x f ( x ) d d x ( sin x ) = cos x Calculation: Function is given as y = sin ( x 2 )

Applied Calculus, 6e WileyPLUS + Loose-leaf

6th Edition

ISBN: 9781119408901

Author: Deborah Hughes-Hallett, Andrew M. Gleason, Patti Frazer Lock, Daniel E. Flath

Publisher: Wiley (WileyPLUS Products)

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Question

Chapter 3.5, Problem 12P

To determine

To find derivative of the below function.

y=sin(x2)

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Chapter 3.5, Problem 11P

Chapter 3.5, Problem 13P

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Chapter 3 Solutions

Applied Calculus, 6e WileyPLUS + Loose-leaf

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To find derivative of the below function. y = sin ( x 2 )

Solution Summary: The author explains how the function is given as y=mathrmsin(x2).

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To find derivative of the below function.

y=sin(x2)

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Chapter 3 Solutions

To find derivative of the below function. y = sin ( x 2 )

Solution Summary: The author explains how the function is given as y=mathrmsin(x2).

Concept explainers

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To find derivative of the below function. y=sin(x2)

Want to see the full answer?

Chapter 3 Solutions

To find derivative of the below function.

y=sin(x2)