Explanation Given: Function f ( x ) = ( 3 x + 8 ) ( 2 x − 5 ) . Formula Used: Product rule of derivative is as follows: ( f . g ) ′ = f ′ . g + f . g ′ Calculation: Function is given as f ( x ) = ( 3 x + 8 ) ( 2 x − 5 ) Derivative of the above function can be calculated using the product rule. f ′ ( x ) = d d x [ ( 3 x + 8 ) ( 2 x − 5 ) ] f ′ ( x ) = [ d d x ( 3 x + 8 ) × ( 2 x − 5 ) ] + [ ( 3 x + 8 ) × d d x ( 2 x − 5 ) ] f ′ ( x ) = [ ( 3 ( 1 ) + 0 ) × ( 2 x − 5 ) ] + [ ( 3 x + 8 ) </

Applied Calculus, 6e WileyPLUS + Loose-leaf

6th Edition

ISBN: 9781119408901

Author: Deborah Hughes-Hallett, Andrew M. Gleason, Patti Frazer Lock, Daniel E. Flath

Publisher: Wiley (WileyPLUS Products)

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Chapter 3.4, Problem 33P

To determine

To find f′(x) and f″(x) for f(x)=(3x+8)(2x−5).

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Chapter 3.4, Problem 32P

Chapter 3.4, Problem 34P

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Applied Calculus, 6e WileyPLUS + Loose-leaf

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To find f ′ ( x ) and f ″ ( x ) for f ( x ) = ( 3 x + 8 ) ( 2 x − 5 ) .

Solution Summary: The author calculates the derivative of the above function using the product rule.

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To find f′(x) and f″(x) for f(x)=(3x+8)(2x−5).

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Chapter 3 Solutions