Explanation 1) Concept: Here, we need to use the concept of interference of waves from thin films. Here, as the reflection causes the phase shift of half wavelength, the position of dark and bright fringes will change. 2) Formula: i) P a t h l e n g t h d i f f e r e n c e = o d d n u m b e r 2 × λ 3) Given: i) The light of wavelength λ diffracts from the slit. ii) The distance of slit is ‘h’ from the principle axis. 4) Calculation: a) As the reflection causes the phase shift of half wavelength, the rays coming at the viewing screen are out of phase. Hence, at the center, it will be a dark fringe. b) As the waves are already out of phase due to reflection from the mirror, for the bright fringes, the waves need further phase shift of half wavelength. So, P a t h l e n g t h d i f f e r n c e = o d d n u m b e r 2 × w a v e l e n g t h where, p a t h l e n g t h d i f f e r e n c e = 2 h s i n θ Here, h is the distance between the slit and the principle axis of lens. So, 2 h s i n θ = m + 1 2 λ , f o r m = 0 , 1 , 2 , …

11th Edition

ISBN: 9781119459170

Author: Halliday

Publisher: WILEY

See similar textbooks

Concept explainers

Dispersion of White Light

Snell’s law is a formula that gives a relation between the angle of incidence and angle of refraction and is given as:

Question

Chapter 35, Problem 104P

To determine

To find:

a. Is the fringe that corresponds to a zero path length difference bright or dark?

b. The expression for the bright fringes

c. The expression for the dark fringes

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 35, Problem 103P

Chapter 35, Problem 105P

Students have asked these similar questions

Please draw a sketch and a FBD

Please draw a sketch and FBD

Please draw a sketch and a FBD

Chapter 35 Solutions

FUND.OF PHYSICS(LL)-PRINT COMP-W/ACCESS

Ch. 35 - Does the spacing between fringes in a two-slit...Ch. 35 - a If you move from one bright fringe in a two-slit...Ch. 35 - Figure 35-22 shows two light rays that are...Ch. 35 - In Fig. 35-23, three pulses of lighta, b, and cof...Ch. 35 - Is there an interference maximum, a minimum, an...Ch. 35 - Figure 35-24a gives intensity I verus position x...Ch. 35 - Figure 35-25 shows two sources S1 and S2 that emit...Ch. 35 - Figure 35-26 shows two rays of light, of...Ch. 35 - Light travels along the length of a 1500-nm-long...Ch. 35 - Figure 35-27a shows the cross section of a...

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

a. Is the fringe that corresponds to a zero path length difference bright or dark? b. The expression for the bright fringes c. The expression for the dark fringes

Concept explainers

To find: a. Is the fringe that corresponds to a zero path length difference bright or dark? b. The expression for the bright fringes c. The expression for the dark fringes

Want to see the full answer?

Chapter 35 Solutions

To find:

a. Is the fringe that corresponds to a zero path length difference bright or dark?

b. The expression for the bright fringes

c. The expression for the dark fringes