BIOLOGY (LOOSELEAF)-W/CONNECT
12th Edition
ISBN: 9781260692181
Author: Raven
Publisher: MCG
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Chapter 34.6, Problem 1LO
Summary Introduction
To discuss: The characteristics and major groups of amphibians.
Introduction: Amphibians belong to the phylum Chordata. Amphibians are tetrapods that evolved from lobe-finned fish. They left the water and enter the land with four legs.
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a) Calculating Transformation Efficiency
For the +DNA/+Amp/+IPTG plate, record the following:
Number of transformants (colonies): _________________
Nanograms of plasmid DNA added: 50 ng
Final recovery volume: 0.50 mL
Volume plated: 0.25 mL
Transformation efficiency equation:
Transformation efficiency = Number of transformants / µg of DNA x Final volume at recovery (mL)/ volume plated (mL)
b) Using the equation above, calculate the transformation efficiency.
c) Describe the success of the transformation efficiency of this demo based on the calculation you did above?
a) What differences would you expect to see between the -DNA/+Amp and +DNA/+Amp plates?
b) Predict the growth you would expect to see on each of the following plates:
– DNA ___________________________________________________________
– DNA/+Amp ______________________________________________________
+DNA/+Amp ______________________________________________________
+DNA/+Amp/+IPTG _________________________________________________
1)Which plate did you see purple/pink/blue bacterial cells? Why did you see this growth? Explain your answer in terms of transformation and plasmids?
2) Calculating Transformation Efficiency
For the +DNA/+Amp/+IPTG plate, record the following:
Number of transformants (colonies): _________________
Nanograms of plasmid DNA added: 50 ng
Final recovery volume: 0.50 mL
Volume plated: 0.25 mL
Transformation efficiency equation:
Transformation efficiency = Number of transformants / µg of DNA x Final volume at recovery (mL)/ volume plated (mL)
3) Using the equation above, calculate the transformation efficiency.
4) Describe the success of the transformation efficiency of this demo based on the calculation you did above?
Chapter 34 Solutions
BIOLOGY (LOOSELEAF)-W/CONNECT
Ch. 34.1 - List the specific characteristics of echinoderms.Ch. 34.1 - Explain what is meant by pentaradial symmetry.Ch. 34.1 - Describe the five extant classes of echinoderms.Ch. 34.2 - List the defining characteristics of chordates.Ch. 34.2 - Prob. 2LOCh. 34.3 - Describe the nonvertebrate chordates and their...Ch. 34.4 - Prob. 1LOCh. 34.4 - Prob. 2LOCh. 34.5 - Prob. 1LOCh. 34.5 - Prob. 2LO
Ch. 34.6 - Prob. 1LOCh. 34.6 - Prob. 2LOCh. 34.7 - Prob. 1LOCh. 34.7 - Prob. 2LOCh. 34.7 - Prob. 3LOCh. 34.8 - Prob. 1LOCh. 34.8 - Prob. 2LOCh. 34.9 - Prob. 1LOCh. 34.9 - Prob. 2LOCh. 34.10 - Describe the characteristics and major groups of...Ch. 34.10 - Prob. 2LOCh. 34.10 - Prob. 3LOCh. 34 - Prob. 1IQCh. 34 - Prob. 2IQCh. 34 - Which of the following structures is not a...Ch. 34 - Which of the following statements regarding all...Ch. 34 - In the figure, item A is the ______ and item B is...Ch. 34 - Prob. 4UCh. 34 - The ____ of the bony fish evolved to counter the...Ch. 34 - Why was the evolution of the pulmonary veins...Ch. 34 - Which of the following groups lacks a...Ch. 34 - All of the following are characteristics of...Ch. 34 - Which of the following evolutionary adaptations...Ch. 34 - The reason that birds and crocodilians both build...Ch. 34 - Prob. 2ACh. 34 - The fact that monotremes lay eggs a. indicates...Ch. 34 - Prob. 1SCh. 34 - Some people state that the dinosaurs have not gone...Ch. 34 - In what respect is the evolutionary...
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- Overview of Transformation Protocol -Prepare competent bacteria for transformation: Treat starter E. coli bacteria with CaCl2and Competent Cell Solution (CCS). Store on ice until transformation procedure. Competent cells are cells that are likely to take up foreign DNA and be transformed. This step increases the likelihood that the E. coli cells will take up the introduced vector and be transformed. -Transformation procedure: Obtain two microcentrifuge tubes containing your competent cells. Label one tube +DNA and one -DNA. Add CaCl2 to both tubes. Add the transformation mix containing the plasmid DNA to the tube labeled +DNA. Do not add any plasmid DNA to the -DNA tube. Incubate both tubes on ice for 10 minutes. Then, place both tubes in a 42\deg C water bath for 45 seconds. Replace the tubes in an ice bucket for 2 minutes. Add recovery broth to both tubes. Incubate both tubes in a 37 C water bath for 5 minutes. Questions: 1) What differences would you expect to see between the…arrow_forwardOverview of Transformation Protocol -Prepare competent bacteria for transformation: Treat starter E. coli bacteria with CaCl2and Competent Cell Solution (CCS). Store on ice until transformation procedure. Competent cells are cells that are likely to take up foreign DNA and be transformed. This step increases the likelihood that the E. coli cells will take up the introduced vector and be transformed. -Transformation procedure: Obtain two microcentrifuge tubes containing your competent cells. Label one tube +DNA and one -DNA. Add CaCl2 to both tubes. Add the transformation mix containing the plasmid DNA to the tube labeled +DNA. Do not add any plasmid DNA to the -DNA tube. Incubate both tubes on ice for 10 minutes. Then, place both tubes in a 42\deg C water bath for 45 seconds. Replace the tubes in an ice bucket for 2 minutes. Add recovery broth to both tubes. Incubate both tubes in a 37 C water bath for 5 minutes. Questions: 1)What is the selectable marker in this experiment? How…arrow_forwardBased on your results, which suspect's DNA best matches the DNA found at the crime scene?arrow_forward
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- is often a good indication of phylogenetic relatedness in phenotypes. Life-cycle patterns Cleavage patterns O Gene expression O Morphological similarityarrow_forwardWhich of the following is a weakness of using 16S rRNA for phylogenetic analyses? It can only go down to the family and genus levels It takes months to complete O Both of the above O None of the abovearrow_forwardAn unrooted tree containing ten unrelated species can become rooted by adding a descendant group related to two of the species. an unrelated outgroup. O a distantly related outgroup. O a descendant related to only one of the species.arrow_forward
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