Automotive Technology: A Systems Approach (MindTap Course List)
6th Edition
ISBN: 9781133612315
Author: Jack Erjavec, Rob Thompson
Publisher: Cengage Learning
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Chapter 34, Problem 7RQ
True or False? No-start, surging, or stalling can be caused by an EGR valve that does not open.
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Chapter 34 Solutions
Automotive Technology: A Systems Approach (MindTap Course List)
Ch. 34 - A rich air-fuel ratio causes HC emissions to...Ch. 34 - What will result from too little EGR flow? And...Ch. 34 - What can result from a charcoal canister that is...Ch. 34 - What happens if a PCV valve is stuck in the open...Ch. 34 - Explain why the I/M 240 and similar tests are...Ch. 34 - How do you test the efficiency of a secondary AIR...Ch. 34 - True or False? No-start, surging, or stalling can...Ch. 34 - List five common causes for high HC emissions.Ch. 34 - Describe carbon monoxide (CO) emissions in...Ch. 34 - A restricted catalytic converter can cause all of...
Ch. 34 - Which of the following statements about EVAP...Ch. 34 - As a catalytic converter begins to deteriorate,...Ch. 34 - How much pressure does a typical EVAP pressure...Ch. 34 - Which of the following exhaust gases is typically...Ch. 34 - Prob. 15RQCh. 34 - While discussing the proper way to test a...Ch. 34 - Prob. 2ASRQCh. 34 - While discussing catalytic converter diagnosis:...Ch. 34 - While discussing EGR valve diagnosis: Technician A...Ch. 34 - While discussing EGR valve diagnosis: Technician A...Ch. 34 - When discussing the diagnosis of a positive back...Ch. 34 - While diagnosing a PCV problem: Technician A says...Ch. 34 - Technician A says that the AIR system should pump...Ch. 34 - While discussing PCV system diagnosis: Technician...Ch. 34 - While discussing EVAP testing: Technician A says...
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- Of the following pairs of material types, indicate whether any of them satisfy the condition that both elements of the pair are generically related to the property of ductility.(A). Yes, ceramics and polymers.(B). No, none of the pairs.(C). Yes, metals and ceramics.(D). Yes, polymers and metals.arrow_forwardBoth Fouriers law of heat conduction and ficks law of mass diffusion can be expressed as Q=-kA(dT/dx). What do the quantities Q, k, a and T represent in a) heat conduction b)mass diffusionarrow_forward(9) Figure Q9 shows a 2 m long symmetric I beam where the upper and lower sections are 2X wide and the middle section is X wide, where X is 31 mm. The I beam sections are all Y=33 mm in depth. The beam is loaded in the middle with a load of Z=39 kN causing reaction forces at either end of the beam's supports. What is the maximum (positive) bending stress experienced in the beam in terms of mega-Pascals? State your answer to the nearest whole number. Y mm Y mm Y mm Xmm 2X mm Figure Q9 Z KN 2 marrow_forward
- (5) Figure Q5 shows a beam which rests on two pivots at positions A and C (as illustrated below). The beam is loaded with a UDL of 100 kN/m spanning from position B and ending at position D (as illustrated). The start location of B is Y=1.2 m from A. The total span of the UDL is twice the length of Z, where Z=2.2 m. What is the bending moment value at position X=2.5 m, (using the convention given to you in the module's formula book). State your answer in terms of kilo-Newton-metres to 1 decimal place. Bending Moment Value? UDL = 100 kN/m A Ym X = ? B Zm Figure Q5 C * Zm Darrow_forwardYou are required to state your answer in millimetres to the nearest whole number. 30 mm 30 mm A. No Valid Answer B. 27 ○ C. 26 O D.33 ○ E. 34 30 mm 50 mm Figure Q14 1marrow_forwardA beam supports a uniform load and an axial load P = 30 kips. If the maximum allowable tensile stress in the beam is 24 ksi and a maximum allowable compressive stress is 20 ksi, what uniform load can the beam support? Assume P passes through the centroid of the section.arrow_forward
- Bending Moment Value? 40 kN 100 kN 100 kN 100 kN 40 kN A B C D E Ym Zm Zm Ym X = ?arrow_forward(4) Figure Q4 shows a symmetrically loaded beam. The beam is loaded at position A (x = 0 m) and the end of the beam at position E with 30 kN. There is an additional load of 101 kN both at position B (Y = 0.87 m), in the middle at C and at position D. The middle section is 2Z, where Z = 0.82 m). Given that the reaction forces at RB and RD both equal 180 kN, calculate the Bending Moment value (using the convention given to you in the module's formula book) at a position of x=2.30m. State your answer in terms of kilo-Newton-metres to one decimal place. Bending Moment Value? 40 kN 100 kN 100 kN 100 kN 40 kN B D E Ym Zm Zm Ym X = ? Figure Q4arrow_forward(8) Figure Q8 shows a T cross-section of a T beam which is constructed from three metal plates each having a width of 12 mm and sectional engths of X=72 mm, Y=65 mm and Z=88 mm, where the plates are used for the web section, and the two flange sections respectively, as llustrated in Figure Q8. Calculate the neutral axis of the T-beam cross-section (as measured from the base) in units of millimetres, stating your answer to the nearest 1 decimal place. Z mm Y mm 12 mm X mm Figure Q8 12 mm 12 mmarrow_forward
- (10) A regular cross-section XXY mm beam, where X-94 m and Y=62 m and 1800 mm long, is loaded from above in the middle with a load of Z=2 kN causing a compressive Bending Stress at the top of the beam and tensile Bending Stress at the bottom of the beam. The beam in addition experiences a tensile end loading in order to reduce the compressive stress in the beam to a near zero value. The configuration of the beam is illustrated in Figure Q10. Calculate the end loading force required in order to reduce total compressive stress experienced in the beam to be near zero? State your answer to the nearest 1 decimal place in terms of kilo-Newtons. Z kN Y mm 1800 mm X mm ? KN Figure Q10 ? KNarrow_forward(12) Figure Q12 shows a framework consisting of 3 upward pointing isosceles triangles and 2 downward pointing isosceles triangles. The framework is loaded at joint F with a downward force of 20 kN. The applied force causes a vertical reaction force at A and D. The design of the framework is such that horizontal base of the isosceles triangles form an angle of 30° degrees with the diagonal members. You are asked to find the internal force in member AE in kilo-Newtons to 1 decimal place (using the standard sign convention given in the module formula booklet)? Select the valid option from the list below. E F S 20 kN RAX = ?? KN 30° 30° 30° 30° 30° 30° A H H B D RAV = ?? KN Roy = ?? KN A. The solution to the problem is found to be -20.0 kN. ○ B. The solution to the problem is found to be -10.0 kN. ○ C. The solution to the problem is found to be +11.5 kN. OD. The solution to the problem is found to be +23.1 kN. O E. No Valid Answerarrow_forward(14) An inverted T beam is constructed from a top square cross-section section and a bottom rectangular cross-section of the same length. The cross-section dimensions of the sections are as follows: - Top Square Section 30 mm x 30 mm (width x depth) Bottom Rectangular Section 50 mm x 30 mm Figure Q14 shows the cross-section arrangement of the plates. Given that compression and tension behave the same in terms of stress analysis. Calculate the distance, Ymax, you would use to calculate a safe bending stress value for further analysis. You are required to state your answer in millimetres to the nearest whole number. 30 mm 30 mm O O A. 34 B. 26 O c. 33 D.27 ○ E. No Valid Answer 30 mm 50 mm Figure Q14 1marrow_forward
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