
CASE STUDY In Example 34.6 (page 1111), we imagined equipping 1950DA, an asteroid on a collision course with the Earth, with a solar sail in hopes of ejecting it from the solar system. We found that the enormous size required for the solar sail makes the plan impossible at this time. Of course, there is no need to eject such an object from the solar system: we only need to change the orbit. A much more pressing problem is Apophis, a 300-m asteroid that may be on a collision course with the Earth and is due to come by on April 13, 2029. It is unlikely to hit the Earth on that pass, but it will return again in 2036. If Apophis passes through a 600-m keyhole on its 2029 pass, it is expected to hit the Earth in 2036. causing great damage. There are plans to deflect Apophis when it comes by in 2029. For example, we could hit it with a 10- to 150-kg impactor accelerated by a solar sail. The impactor is launched from the Earth to start orbiting the Sun in the same direction as the Earth and Apophis. The idea is to use a solar sail to accelerate the impactor so that it reverses direction and collides head-on with Apophis at 80–90 km/s and thereby keeps Apophis out of the keyhole. Consider the momentum in the impactor’s orbit (Fig. P34.75) when the solar sail makes an angle of θ = 60° with the tangent to its orbit. Current solar sails may be about 40 m on a side, but the hope is to construct some that are about 160 m on a side. Estimate the impactor’s tangential acceleration when it is about 1 AU from the Sun. Keep in mind that the sail is neither a perfect absorber nor a perfect reflector, and a heavier impactor would presumably be equipped with a larger sail. Don’t be surprised by what may seem like a very small acceleration.
FIGURE P34.75

Want to see the full answer?
Check out a sample textbook solution
Chapter 34 Solutions
Physics for Scientists and Engineers: Foundations and Connections
- Using Coulomb's Law, calculate the magnitude of the electrical force between two protons located 1 meter apart from each other. (Give your answer as the number of Newtons but as usual you only need to include the number, not the unit label.)arrow_forwardPart A You want to get an idea of the magnitude of magnetic fields produced by overhead power lines. You estimate that a transmission wire is about 12 m above the ground. The local power company tells you that the line operates at 12 kV and provide a maximum of 60 MW to the local area. Estimate the maximum magnetic field you might experience walking under such a power line, and compare to the Earth's field. [For an ac current, values are rms, and the magnetic field will be changing.] Express your answer using two significant figures. ΟΤΕ ΑΣΦ VAΣ Bmax= Submit Request Answer Part B Compare to the Earth's field of 5.0 x 10-5 T. Express your answer using two significant figures. Ο ΑΣΦ B BEarth ? ? Tarrow_forwardHo propel 9-kN t. Boat 27. An elevator accelerates downward at 2.4 m/s². What force does the elevator's floor exert on a 52-kg passenger?arrow_forward
- 16. 17 A CUIN Starting from rest and undergoing constant acceleration, a 940-kg racing car covers 400 m in 4.95 s. Find the force on the car.arrow_forward----- vertical diste Section 4.6 Newton's Third Law 31. What upward gravitational force does a 5600-kg elephant exert on Earth?arrow_forward64. Two springs have the same unstretched length but different spring constants, k₁ and k₂. (a) If they're connected side by side and stretched a distance x, as shown in Fig. 4.24a, show that the force exerted by the combination is (k₁ + k₂)x. (b) If they're con- nected end to end (Fig. 4.24b) and the combination is stretched a distance x, show that they exert a force k₁k2x/(k₁ + k₂). www (a) FIGURE 4.24 Problem 65 www (b)arrow_forward
- 65. Although we usually write Newton's second law for one-dimensional motion in the form F =ma, which holds when mass is constant, d(mv) a more fundamental version is F = . Consider an object dt whose mass is changing, and use the product rule for derivatives to show that Newton's law then takes the form F dm = ma + v dtarrow_forwardIf a proton is located on the x-axis in some coordinate system at x0 = -3.2 x 10-5 meters, what is the x-component of the Electric Field due to this proton at a position x = +3.2 x 10-5 meters and on the x axis as the y-axis is 0 giving a number of Newtons/Coulomb?arrow_forwardConsider a single square loop of wire of area A carrying a current I in a uniform magnetic field of strength B. The field is pointing directly up the page in the plane of the page. The loop is oriented so that the plane of the loop is perpendicular to the plane of the page (this means that the normal vector for the loop is always in the plane of the page!). In the illustrations below the magnetic field is shown in red and the current through the current loop is shown in blue. The loop starts out in orientation (i) and rotates clockwise, through orientations (ii) through (viii) before returning to (i). (i) Ø I N - - I N - (iii) (iv) (v) (vii) (viii) a) [3 points] For each of the eight configurations, draw in the magnetic dipole moment vector μ of the current loop and indicate whether the torque on the dipole due to the magnetic field is clockwise (CW), counterclockwise (CCW), or zero. In which two orientations will the loop experience the maximum magnitude of torque? [Hint: Use the…arrow_forward
- Please help with calculating the impusle, thanks! Having calculated the impact and rebound velocities of the ping pong ball and the tennis ball calculate the rebounding impulse: 1.Measure the weight of the balls and determine their mass. Tennis ball: 0.57 kg Ping Pong Ball: 0.00246 kg The impulse, I, is equal to the change in momentum, Pf-Pi. Note the sign change, i.e., going down is negative and up is positive. The unit for momentum is kg-m/s. The change is momentum, impulse, is often givens the equivalent unit of N-S, Newton-Secondarrow_forward5. Three blocks, each with mass m, are connected by strings and are pulled to the right along the surface of a frictionless table with a constant force of magnitude F. The tensions in the strings connecting the masses are T1 and T2 as shown. m T1 T2 F m m How does the magnitude of tension T₁ compare to F? A) T₁ = F B) T₁ = (1/2)F C) T₁ = (1/3)F D) T₁ = 2F E) T₁ = 3Farrow_forwardUsing Coulombs Law, what is the magnitude of the electrical force between two protons located 1 meter apart from each other in Newtons?arrow_forward
- College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningPrinciples of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and Engineers with Modern ...PhysicsISBN:9781337553292Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
- Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage LearningCollege PhysicsPhysicsISBN:9781285737027Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningModern PhysicsPhysicsISBN:9781111794378Author:Raymond A. Serway, Clement J. Moses, Curt A. MoyerPublisher:Cengage Learning





