BIO What Is the Smallest Thing We Can See? The smallest object we can resolve with our eye is limited by the size of the light receptor cells in the retina. In order for us to distinguish any detail in an object, its image cannot be any smaller than a single retinal cell. Although the size depends on the type of cell (rod or cone), a diameter of a few microns ( μ m) is typical near the center of the eye. We shall model the eye as a sphere 2.50 cm in diameter with a single thin lens at the front and the retina at the rear, with light receptor cells 5.0 μ m in diameter. (a) What is the smallest object you can resolve at a near point of 25 cm? (b) What angle is subtended by this object at the eye? Express your answer in units of minutes (1° = 60 min), and compare it with the typical experimental value of about 1.0 min. ( Note: There are other limitations, such as the bending of light as it passes through the pupil, but we shall ignore them here.)
BIO What Is the Smallest Thing We Can See? The smallest object we can resolve with our eye is limited by the size of the light receptor cells in the retina. In order for us to distinguish any detail in an object, its image cannot be any smaller than a single retinal cell. Although the size depends on the type of cell (rod or cone), a diameter of a few microns ( μ m) is typical near the center of the eye. We shall model the eye as a sphere 2.50 cm in diameter with a single thin lens at the front and the retina at the rear, with light receptor cells 5.0 μ m in diameter. (a) What is the smallest object you can resolve at a near point of 25 cm? (b) What angle is subtended by this object at the eye? Express your answer in units of minutes (1° = 60 min), and compare it with the typical experimental value of about 1.0 min. ( Note: There are other limitations, such as the bending of light as it passes through the pupil, but we shall ignore them here.)
BIO What Is the Smallest Thing We Can See? The smallest object we can resolve with our eye is limited by the size of the light receptor cells in the retina. In order for us to distinguish any detail in an object, its image cannot be any smaller than a single retinal cell. Although the size depends on the type of cell (rod or cone), a diameter of a few microns (μm) is typical near the center of the eye. We shall model the eye as a sphere 2.50 cm in diameter with a single thin lens at the front and the retina at the rear, with light receptor cells 5.0 μm in diameter. (a) What is the smallest object you can resolve at a near point of 25 cm? (b) What angle is subtended by this object at the eye? Express your answer in units of minutes (1° = 60 min), and compare it with the typical experimental value of about 1.0 min. (Note: There are other limitations, such as the bending of light as it passes through the pupil, but we shall ignore them here.)
In a patient with hyperopia (farsightedness), an optometrist knows that
Group of answer choices
the far point is a few centimeters from the patient's eyes.
the near point and far point are at the same location.
the near point is at infinity.
the near point is many 10s of centimeters from the patient's eyes.
the far point is several 10s of centimeters from the patient's eyes.
Estimate the height of the building shown in the following figure by the method of
triangulation. The person is standing 5 meters from a pole, which is 15 meters from the
building. The person's vision perceives the top of the pole aligned with the top of the building.
The person is approximately 1.75 meters and the pole is approximately 3.5 meters.
15 m
b) Estimate the volume and mass of water that exists in a lake. The shape of the lake is
approximately circular, it is almost 500 meters in diameter and is supposed to have a
average depth of 20.0 meters. Remember that the density of water is equal to
1000 Kg / m3
d= 500m
h = 20.0m
An object is placed to the left of a concave lens with focal length -10 cm such that the image produced by the lens is exactly half the size of the object.
In a neat and organized fashion, write out a solution which includes the following:
A sketch of the physical situation with all given physical quantities clearly labeled.
Draw a ray diagram showing the object, the lens, and the image.
Determine the location of the object and the image. Clearly show all steps, starting from generalized equations. Explain your mathematical work in words. Your explanation should cover both what you did and the thought process behind why you did that.
Evaluate your answer to determine whether it is reasonable or not. Consider all aspects of your answer (the numerical value, sign, and units) in your evaluation.
Answer all questions from 1-4
In 1 make sure the physical situation is sketch and label
In 2 make sure the ray diagram is draw
In 4 why the answer is reasonable
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