95 through 100 GO 95, 96, 99 Three-lens systems . In Fig. 34-49, stick figure O (the object) stands on the common central axis of three thin, symmetric lenses, which are mounted in the boxed regions. Lens 1 is mounted within the boxed region closest to O , which is at object distance p 1 . Lens 2 is mounted within the middle boxed region, at distance d 12 from lens 1. Lens 3 is mounted in the farthest boxed region, at distance d 23 from lens 2. Each problem in Table 34-10 refers to a different combination of lenses and different values for distances, which are given in centimeters. The type of lens is indicated by C for converging and D for diverging; the number after C or D is the distance between a lens and either of the focal points (the proper sign of the focal distance is not indicated). Find (a) the image distance i 3 for the (final) image produced by lens 3 (the final image produced by the system) and (b) the overall lateral magnification M for the system, including signs. Also, determine whether the final image is (c) real (R) or virtual (V), (d) inverted (I) from object O or noninverted (NI), and (e) on the same side of lens 3 as object O or on the opposite side. p 1 Lens 1 d 12 Lens 2 d 23 Lens 3 (a) i 3 (b) M (c) R/V (d) I/NI (e) Side 95 +12 C, 8.0 28 C, 6.0 8.0 C, 6.0 Figure 34-49 Problems 95 through 100.
95 through 100 GO 95, 96, 99 Three-lens systems . In Fig. 34-49, stick figure O (the object) stands on the common central axis of three thin, symmetric lenses, which are mounted in the boxed regions. Lens 1 is mounted within the boxed region closest to O , which is at object distance p 1 . Lens 2 is mounted within the middle boxed region, at distance d 12 from lens 1. Lens 3 is mounted in the farthest boxed region, at distance d 23 from lens 2. Each problem in Table 34-10 refers to a different combination of lenses and different values for distances, which are given in centimeters. The type of lens is indicated by C for converging and D for diverging; the number after C or D is the distance between a lens and either of the focal points (the proper sign of the focal distance is not indicated). Find (a) the image distance i 3 for the (final) image produced by lens 3 (the final image produced by the system) and (b) the overall lateral magnification M for the system, including signs. Also, determine whether the final image is (c) real (R) or virtual (V), (d) inverted (I) from object O or noninverted (NI), and (e) on the same side of lens 3 as object O or on the opposite side. p 1 Lens 1 d 12 Lens 2 d 23 Lens 3 (a) i 3 (b) M (c) R/V (d) I/NI (e) Side 95 +12 C, 8.0 28 C, 6.0 8.0 C, 6.0 Figure 34-49 Problems 95 through 100.
95 through 100 GO 95, 96, 99 Three-lens systems. In Fig. 34-49, stick figure O (the object) stands on the common central axis of three thin, symmetric lenses, which are mounted in the boxed regions. Lens 1 is mounted within the boxed region closest to O, which is at object distance p1. Lens 2 is mounted within the middle boxed region, at distance d12 from lens 1. Lens 3 is mounted in the farthest boxed region, at distance d23 from lens 2. Each problem in Table 34-10 refers to a different combination of lenses and different values for distances, which are given in centimeters. The type of lens is indicated by C for converging and D for diverging; the number after C or D is the distance between a lens and either of the focal points (the proper sign of the focal distance is not indicated).
Find (a) the image distance i3 for the (final) image produced by lens 3 (the final image produced by the system) and (b) the overall lateral magnification M for the system, including signs. Also, determine whether the final image is (c) real (R) or virtual (V), (d) inverted (I) from object O or noninverted (NI), and (e) on the same side of lens 3 as object O or on the opposite side.
Find the ratio of the diameter of silver to iron wire, if they have the same resistance per unit length (as they might in household wiring).
d.
Ag
dFe
= 2.47
×
Find the ratio of the diameter of silver to iron wire, if they have the same resistance per unit length (as they might in household wiring).
d
Ag
= 2.51
dFe
×
Show that the units 1 v2/Q = 1 W, as implied by the equation P = V²/R.
Starting with the equation P = V²/R, we can get an expression for a watt in terms of voltage and resistance. The units for voltage, V, are equivalent to [?
v2
v2
A, are equivalent to J/C ✓ X . Therefore, 1
= 1
= 1 A V1 J/s
Ω
V-A X
= 1 W.
. The units for resistance, Q, are equivalent to ?
The units for current,
Physics for Scientists and Engineers: A Strategic Approach, Vol. 1 (Chs 1-21) (4th Edition)
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