In Lesson 3-1, we studied a cab ride by looking at the price for certain distances in table and graph form. We found that the initial cost of starting the trip was $5.10, which means that you’d pay $5.10 for zero miles traveled. We also found that the slope of the line was $2.60, which means that you’d pay $2.60 per mile. Using what we learned in Lesson 3-2, we can write a formula that describes the cost of a trip ( C ) in terms of miles traveled ( m ): C = 5.1 + 2.6 m . If you have budgeted $18 for a cab ride to tour the downtown area, how far can you go? Set up and solve an equation.
In Lesson 3-1, we studied a cab ride by looking at the price for certain distances in table and graph form. We found that the initial cost of starting the trip was $5.10, which means that you’d pay $5.10 for zero miles traveled. We also found that the slope of the line was $2.60, which means that you’d pay $2.60 per mile. Using what we learned in Lesson 3-2, we can write a formula that describes the cost of a trip ( C ) in terms of miles traveled ( m ): C = 5.1 + 2.6 m . If you have budgeted $18 for a cab ride to tour the downtown area, how far can you go? Set up and solve an equation.
Solution Summary: The author calculates the distance a person can travel at 18 when the cost is given by the equation C=5.1+2.6m.
In Lesson 3-1, we studied a cab ride by looking at the price for certain distances in table and graph form. We found that the initial cost of starting the trip was $5.10, which means that you’d pay $5.10 for zero miles traveled. We also found that the slope of the line was $2.60, which means that you’d pay $2.60 per mile. Using what we learned in Lesson 3-2, we can write a formula that describes the cost of a trip (C) in terms of miles traveled (m):
C
=
5.1
+
2.6
m
.
If you have budgeted $18 for a cab ride to tour the downtown area, how far can you go? Set up and solve an equation.
For each graph below, state whether it represents a function.
Graph 1
24y
Graph 2
Graph 3
4
2
-8
-6 -4
-2
-2
2 4 6
Function?
○ Yes
○ No
○ Yes
○ No
Graph 4
Graph 5
8
Function?
Yes
No
Yes
No
-2.
○ Yes
○ No
Graph 6
4
+
2
4
-8 -6 -4 -2
2 4 6
8
Yes
-4++
No
Students were asked to simplify the expression (secØ - cosØ)/secØ Two students' work is given.Student A: step 1 secØ/secØ - cosØ/secØstep 2 cosØ/1 - (1/cosØ)step 3 1 - cos^2Østep 4 sin^2ØStudent B: step 1 (1/cosØ)-cosØ)/secØstep 2 (1 - cos^2Ø/cosØ)/secØstep 3 sin^2Ø/cos^2Østep 4 tan^2ØPart A: Which student simplified the expression incorrectly? Explain the errors that were made or the formulas that were misused.Part B: Complete the student's solution correctly, beginning with the location of the error.
Although 330° is a special angle on the unit circle, Amar wanted to determine its coordinates using the sum and difference formulas.Part A: Determine cos 330° using the cosine sum identity. Be sure to include all necessary work.Part B: Determine sin 330° using the sine difference identity. Be sure to include all necessary work.
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