PHYSICS FOR SCI & ENGR W WEBASSIGN
PHYSICS FOR SCI & ENGR W WEBASSIGN
10th Edition
ISBN: 9781337888486
Author: SERWAY
Publisher: CENGAGE L
Question
100%
Book Icon
Chapter 33, Problem 1P

(a)

To determine

The time rate of increase of electric field between the plates.

(a)

Expert Solution
Check Mark

Answer to Problem 1P

The time rate of increase of electric field between the plates is 7.19×1011V/ms .

Explanation of Solution

Given info: The current is 0.200A , the radius of the circular plate is 10.0cm and the separation distance between the plates is 4.00mm .

The value of permittivity of free space is 8.85×1012F/m and the value of the permeability constant is ×107H/m

The area of the circular plate is,

A=πr2

Here,

r is the radius of the circular plate.

The formula for the capacitance of the capacitor is.

C=Aε0d=πr2ε0d

Here,

ε0 is the permittivity of free space.

d is the separation between the plates.

Substitute 10.0cm for r , 8.85×1012F/m for ε0 and 4.00mm for d in above equation to find C .

C=π(10.0cm(102m1cm))2(8.85×1012F/m)4.00mm(103m1mm)=6.95×1011F

Thus, the capacitance of the capacitor is 6.95×1011F .

The formula for the capacitance of the capacitor is.

C=QVV=QC

Here,

Q is the charge of the plates.

V is the potential of the plates.

Differentiate the above equation with respect to time.

dVdt=dQdtC

The formula for the current is,

I=dQdt

Then,

dVdt=IC

The formula for the electric field is,

E=Vd

Differentiate the above equation with respect to time.

dEdt=1ddVdt

Substitute IC for dVdt in above equation.

dEdt=ICd

Substitute 0.200A for I , 6.95×1011F for C and 4.00mm for d in above equation to find dEdt .

dEdt=0.200A(6.95×1011F)(4.00mm(103m1mm))=7.19×1011V/ms

Conclusion:

Therefore, the time rate of increase of electric field between the plates is 7.19×1011V/ms .

(b)

To determine

The magnetic field between the plates 5.00cm from the centre.

(b)

Expert Solution
Check Mark

Answer to Problem 1P

The magnetic field between the plates 5.00cm from the centre is 2.0×107T .

Explanation of Solution

Given info: The current is 0.200A , the radius of the circular plate is 10.0cm and the separation distance between the plates is 4.00mm .

The formula for the electric flux through the circular plate is,

ΦE=EAdΦEdt=AdEdt=πr2dEdt

The Maxwell’s equation is.

Bds=ε0μ0dΦEdtB(2πr)=ε0μ0πr2dEdtB=(rε0μ02)dEdt

Substitute 5.00cm for r , 8.85×1012F/m for ε0 , ×107H/m for μ0 and 7.19×1011V/ms for dEdt in above equation to find B .

B=((5.00cm(102m1cm))(8.85×1012F/m)(×107H/m)2)(7.19×1011V/ms)=1.9990×107T2.0×107T

Conclusion:

Therefore, the magnetic field between the plates 5.00cm from the centre is 2.0×107T .

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
••63 SSM www In the circuit of Fig. 27-65, 8 = 1.2 kV, C = 6.5 µF, R₁ S R₂ R3 800 C H R₁ = R₂ = R3 = 0.73 MQ. With C completely uncharged, switch S is suddenly closed (at t = 0). At t = 0, what are (a) current i̟ in resistor 1, (b) current 2 in resistor 2, and (c) current i3 in resistor 3? At t = ∞o (that is, after many time constants), what are (d) i₁, (e) i₂, and (f) iz? What is the potential difference V2 across resistor 2 at (g) t = 0 and (h) t = ∞o? (i) Sketch V2 versus t between these two extreme times. Figure 27-65 Problem 63.
Thor flies by spinning his hammer really fast from a leather strap at the end of the handle, letting go, then grabbing it and having it pull him. If Thor wants to reach escape velocity (velocity needed to leave Earth’s atmosphere), he will need the linear velocity of the center of mass of the hammer to be 11,200 m/s. Thor's escape velocity is 33532.9 rad/s, the angular velocity is 8055.5 rad/s^2. While the hammer is spinning at its maximum speed what impossibly large tension does the leather strap, which the hammer is spinning by, exert when the hammer is at its lowest point? the hammer has a total mass of 20.0kg.
If the room’s radius is 16.2 m, at what minimum linear speed does Quicksilver need to run to stay on the walls without sliding down?  Assume the coefficient of friction between Quicksilver and the wall is 0.236.

Chapter 33 Solutions

PHYSICS FOR SCI & ENGR W WEBASSIGN

Ch. 33 - A diathermy machine, used in physiotherapy,...Ch. 33 - The distance to the North Star, Polaris, is...Ch. 33 - A radar pulse returns to the transmitterreceiver...Ch. 33 - The speed of an electromagnetic wave traveling in...Ch. 33 - You are working for SETI, the Search for...Ch. 33 - Review. A microwave oven is powered by a...Ch. 33 - Verify by substitution that the following...Ch. 33 - Why is the following situation impossible? An...Ch. 33 - At what distance from the Sun is the intensity of...Ch. 33 - If the intensity of sunlight at the Earths surface...Ch. 33 - Prob. 14PCh. 33 - High-power lasers in factories are used to cut...Ch. 33 - Review. Model the electromagnetic wave in a...Ch. 33 - Prob. 17PCh. 33 - Prob. 18PCh. 33 - Prob. 19PCh. 33 - Prob. 20PCh. 33 - A 25.0-mW laser beam of diameter 2.00 mm is...Ch. 33 - The intensity of sunlight at the Earths distance...Ch. 33 - Prob. 23PCh. 33 - Prob. 24PCh. 33 - Prob. 25PCh. 33 - Assume the intensity of solar radiation incident...Ch. 33 - Extremely low-frequency (ELF) waves that can...Ch. 33 - A large, flat sheet carries a uniformly...Ch. 33 - Prob. 29PCh. 33 - Prob. 30PCh. 33 - Prob. 31PCh. 33 - An important news announcement is transmitted by...Ch. 33 - Assume the intensity of solar radiation incident...Ch. 33 - Classify waves with frequencies of 2 Hz, 2 kHz, 2...Ch. 33 - The eye is most sensitive to light having a...Ch. 33 - Prob. 36APCh. 33 - You are working as a radio technician. One day,...Ch. 33 - One goal of the Russian space program is to...Ch. 33 - The intensity of solar radiation at the top of the...Ch. 33 - The Earth reflects approximately 38.0% of the...Ch. 33 - Consider a small, spherical particle of radius r...Ch. 33 - Consider a small, spherical particle of radius r...Ch. 33 - Review. A 1.00-m-diameter circular mirror focuses...Ch. 33 - Prob. 44APCh. 33 - Prob. 45APCh. 33 - You may wish to review Sections 16.4 and 16.8 on...Ch. 33 - You are working at NASA, in a division that is...Ch. 33 - Prob. 48APCh. 33 - Prob. 49APCh. 33 - Prob. 50CPCh. 33 - Prob. 51CP
Knowledge Booster
Background pattern image
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Text book image
University Physics Volume 2
Physics
ISBN:9781938168161
Author:OpenStax
Publisher:OpenStax
Text book image
Physics for Scientists and Engineers: Foundations...
Physics
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Cengage Learning
Text book image
Glencoe Physics: Principles and Problems, Student...
Physics
ISBN:9780078807213
Author:Paul W. Zitzewitz
Publisher:Glencoe/McGraw-Hill
Text book image
College Physics
Physics
ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:OpenStax College
Text book image
Physics for Scientists and Engineers, Technology ...
Physics
ISBN:9781305116399
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning