
Concept explainers
(a)
The focal length of eyepiece.
(a)

Explanation of Solution
Given:
Magnifying power of microscope is
The angular magnification of eyepiece is
The distance of objective lens from eyepiece is
Formula used:
Write expression for angular magnification of eyepiece.
Here,
Calculation:
Substitute
Conclusion:
Thus, the focal length of eyepiece is
(b)
The location object so that it is in focus for normal eye.
(b)

Explanation of Solution
Given:
Magnifying power of microscope is
The angular magnification of eyepiece is
The distance of objective lens from eyepiece is
Formula used:
Write expression for angular magnification of eyepiece.
Here,
Write expression for image distance.
Write expression for magnifying power of microscope.
Rearrange above expression for
Substitute
Substitute
Rearrange above expression for
Calculation:
Substitute
Substitute
Conclusion:
Thus, the object is
(c)
The focal length of objective lens.
(c)

Explanation of Solution
Given:
Magnifying power of microscope is
The angular magnification of eyepiece is
The distance of objective lens from eyepiece is
Formula used:
Write expression for angular magnification of eyepiece.
Here,
Write expression for image distance.
Write expression for magnifying power of microscope.
Rearrange above expression for
Substitute
Substitute
Rearrange above expression for
Write expression for lens equation for objective lens.
Calculation:
Substitute
Substitute
Substitute
Conclusion:
Thus, the focal length of objective lens is
Want to see more full solutions like this?
Chapter 32 Solutions
Physics for Scientists and Engineers
- An object is placed 24.1 cm to the left of a diverging lens (f = -6.51 cm). A concave mirror (f= 14.8 cm) is placed 30.2 cm to the right of the lens to form an image of the first image formed by the lens. Find the final image distance, measured relative to the mirror. (b) Is the final image real or virtual? (c) Is the final image upright or inverted with respect to the original object?arrow_forwardConcept Simulation 26.4 provides the option of exploring the ray diagram that applies to this problem. The distance between an object and its image formed by a diverging lens is 5.90 cm. The focal length of the lens is -2.60 cm. Find (a) the image distance and (b) the object distance.arrow_forwardPls help ASAParrow_forward
- Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and Engineers, Technology ...PhysicsISBN:9781305116399Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage Learning
- University Physics Volume 3PhysicsISBN:9781938168185Author:William Moebs, Jeff SannyPublisher:OpenStaxCollege PhysicsPhysicsISBN:9781285737027Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningCollege PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning





