Chapter 32, Problem 32.2QAP

Interpretation Introduction

Interpretation:

The half-life of ß emitter that is potassium -42 is 12.36h. The fraction of radionuclide is to be determined from the sample of 1,10,20,30,40,50,60,70,80,90 and 100h.The graph is to be plotted between the fraction remaining and the time which is required for the fraction to fall 1% is to be determined.

Concept introduction:

According to first order of kinetics:

$\ln \left(\frac{N}{N_0}\right)=-\lambda t$

Here, N and N_o are final and initial concentrations, $\lambda$ is decay constant and t is time.

$t_{1/2}\left(half-time\right)=\ln \frac{2}{\lambda }$

Here, $t_{1/2}$ is half-life time.